A tritium nucleus is formed by combining two neutrons and a proton. the mass of this nucleus is 9.106 × 10–3 universal mass unit

Question

3 months ago

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A tritium nucleus is formed by combining two neutrons and a proton. the mass of this nucleus is 9.106 × 10–3 universal mass unit

less than the combined mass of the particles from which it is formed. approximately how much energy is released when this nucleus is formed.

Chemistry

2 answers:

lions [2.9K] · Answer 1 · 2026-02-28T17:34:20+03:00

lions [2.9K]3 months ago

7 0

E = mc²

where E = energy produced

m = mass of the nucleus

C = speed of light

m = 9.106 x 10⁻³ x 1.67 x 10⁻²⁷ kg

C = 3 x 10⁸ m/s, thus C² = 9 x 10¹⁶

E = 1.37 x 10⁻¹² J

VMariaS [2.9K] · Answer 2 · 2026-02-28T17:35:49+03:00

Answer: The energy released is, $136.043\times 10^{-14}J$

Explanation:

According to Einstein's formula, energy equals mass multiplied by the square of the speed of light.

The formula is:

$E=m\times c^2$

where,

E = energy

c = speed of light = $3\times 10^8m/s$

m = mass of nucleus = $9.106\times 10^{-3}amu$

Transforming the mass of the nucleus from 'amu' to 'Kg':

Thus, $1amu=1.66\times 10^{-27}Kg$

So, $9.106\times 10^{-3}amu=(9.106\times 10^{-3})\times (1.66\times 10^{-27})Kg$

We can now insert the provided values into the formula, leading us to the amount of energy produced.

$E=[(9.106\times 10^{-3})\times (1.66\times 10^{-27})Kg]\times (3\times 10^8m/s)^2$

$E=136.043\times 10^{-14}J$

Consequently, the energy released is, $136.043\times 10^{-14}J$