Answer: The calculated moles of
that need to be added is 0.37 mol.
Explanation:
The chemical equation in question is:

Initially, the molar quantities are as follows: 2.99, x, 0, 0
At equilibrium: (2.99-1.30), (x-1.30), 1.30, 1.30
= 1.69.
The equation for the equilibrium constant is given by:
![K_c=\frac{[SO_3][NO]}{[SO_2][NO_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BSO_3%5D%5BNO%5D%7D%7B%5BSO_2%5D%5BNO_2%5D%7D)
Now substituting the provided values into this equation yields:

x = 1.67 mol.
The moles of
needed to be added is (x-1.30) = (1.67-1.30) = 0.37 mol.