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4 days ago

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For the chemical equation SO 2 ( g ) + NO 2 ( g ) − ⇀ ↽ − SO 3 ( g ) + NO ( g ) SO2(g)+NO2(g)↽−−⇀SO3(g)+NO(g) the equilibrium co

nstant at a certain temperature is 2.70 . 2.70. At this temperature, calculate the number of moles of NO 2 ( g ) NO2(g) that must be added to 2.99 mol SO 2 ( g ) 2.99 mol SO2(g) in order to form 1.30 mol SO 3 ( g ) 1.30 mol SO3(g) at equilibrium.

1 answer:

lions [985]4 days ago

3 0

Answer: The calculated moles of $NO_2$ that need to be added is 0.37 mol.

Explanation:

The chemical equation in question is:

$SO_2(g)+NO_2(g)\rightleftharpoons SO_3(g)+NO(g)$

Initially, the molar quantities are as follows: 2.99, x, 0, 0

At equilibrium: (2.99-1.30), (x-1.30), 1.30, 1.30

= 1.69.

The equation for the equilibrium constant is given by:

$K_c=\frac{[SO_3][NO]}{[SO_2][NO_2]}$

Now substituting the provided values into this equation yields:

$2.70=\frac{(1.30)\times (1.30)}{(1.69)\times (x-1.30)}$

x = 1.67 mol.

The moles of $NO_2$ needed to be added is (x-1.30) = (1.67-1.30) = 0.37 mol.

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The [H3O+] in a solution is increased to twice the original concentration. Which change could occur in the pH? 2.0 to 4.0 1.7 to

KiRa [971]

Answer: second option: 1.70 to 1.40

Explanation:

1) pH is defined using the formula pH = - log [H₃O⁺]

2) Given that the initial concentration is x and after doubling it becomes 2x, we calculate:

pHi = - logx
pHf = - log 2x = - log 2 - logx

Thus, pHf - pHi = - log2 - logx - (- logx) = - log2 ≈ - 0.30

⇒ pHi - pHf = 0.30, indicating that the final pH (with twice the hydronium ions) is 0.30 lower than the starting pH.

3) The only option that indicates a 0.30 decline in pH is the second one: from 1.70 to 1.40. Therefore, that is the correct choice.

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If the density of carbon tetrachloride is 1.59 g/ml, what is the volume in l, of 4.21 kg of carbon tetrachloride

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Density is defined as the mass-to-volume ratio. The formula for density can be expressed as:

$density = \frac{mass}{volume}$ -(1)

The density for carbon tetrachloride is provided as $1.59 g/ml$ (given).

The mass of carbon tetrachloride is $4.21 kg$ (as given).

Since, $1 kg = 1000 g$

Thus, $4.21 kg = 4210 g$

Utilizing the values in formula (1):

$1.59 g/mL = \frac{4210 g}{volume}$

$volume = \frac{4210 g}{1.59 g/mL}$

$volume = 2647.799 mL$

Since, $1 mL = 0.001 L$

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Answer:- 0.134 seconds

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Unit conversion is needed from miles to meters since the speed is given in meters per second.

1 mile = 1609.34 meters

Thus, $24900mile(\frac{1609.34meter}{mile})$

= 40072566 meters

Now, $speed=\frac{distance}{time}$

Rearranged for time, that gives: $time=\frac{distance}{speed}$

Inserting the values:

$time=\frac{40072566meter}{2.988*10^8\frac{meter}{second}}$

= 0.134 seconds

Hence, light would take 0.134 seconds to traverse the indicated distance. The answer without the unit is 0.134.

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Mobile phase: The component in which the mixture is dissolved is referred to as the mobile phase.

Stationary phase: This is an adsorbent medium that remains in place while a liquid or gas passes over its surface, thus remaining stationary.

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If you disregard the negligible volume of the Ca(OH)2 itself, the resulting total volume of a 0.680M solution created by dissolving 55.0g of Ca(OH)2 in an appropriate amount of water would be 1.09L.

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