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posledela
2 months ago
7

A 7.27-gram sample of a compound is dissolved in 250 grams of benzene. The freezing point of this solution is 1.02°C below that

of pure benzene. What is the molar mass of this compound? (Note: Kf for benzene = 5.12°C/m.) Ignore significant figures for this problem:_________.
a. 36.5 g/mol
b. 146 g/mol
c. 292 g/mol
d. 5.79 g/mol
e. 73.0 g/mol
Chemistry
1 answer:
lorasvet [2.7K]2 months ago
5 0

Answer:146 g/mol → option b.

Explanation:

This problem deals with freezing point depression. The colligative property formula for this is:

ΔT = Kf. m. i

We assume i = 1, indicating our compound is non-electrolytic.

ΔT represents the difference in freezing temperature of the pure solvent and the solution = 1.02 °C

m stands for molality (mol of solute per kg of solvent)

We convert the mass of the solvent (benzene) to kg → 250 g. 1 kg/1000 = 0.250 kg.

Substituting gives us → 1.02°C = 5.12°C/mol/kg. mol/ 0.250kg. 1

1.02°C / 5.12 mol/kg/°C = mol/ 0.250kg

0.19922 mol/kg = mol/ 0.250kg

mol = 0.19922. 0.250kg → 0.0498 mol

Calculating molar mass = g/mol → 7.27 g / 0.0498mol = 146 g/mol

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Response: 1-methoxy-2,4-dinitrobenzene

Rationale:

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1 month ago
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Put the following elements into five pairs of elements that have similar chemical reactivity: F, Sr, P, Ca, O, Br, Rb, Sb, Li, S
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Explanation:

Elements provided:

  F, Sr, P, Ca, O, Br, Rb, Sb, Li, S

Elements sharing similar reactivity belong to the same group in the periodic table, indicating that those in the same column exhibit comparable reactivity. Here are the identified groupings:

  Li and Rb are alkali metals in group 1

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3 months ago
How many molecules are in 13.5g of sulfur dioxide, so2?
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2 months ago
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Response:

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I hope this helps!

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