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hjlf
4 months ago
8

Two glasses labeled A and B contain equal amounts of water at different temperatures. Kim put an antacid tablet into each of the

two glasses. The table shows the time taken by the tablet to dissolve completely in the two glasses.
Antacid Experiment
Glass --> Time
A --> 40 seconds
B --> 10 seconds

Which of the following statements is correct?

A. The water in Glass A is warmer than the water in Glass B; therefore, the water particles in Glass A are stationary.

B. The water in Glass A is cooler than the water in Glass B; therefore, the water particles in Glass A are stationary.

C. The water in Glass A is warmer than the water in Glass B; therefore, the particles in Glass A move faster.

D. The water in Glass A is cooler than the water in Glass B; therefore, the particles in Glass A move slower.
Chemistry
2 answers:
eduard [2.7K]4 months ago
6 0

Answer:

The correct statement is D. The water in Glass A is at a lower temperature compared to Glass B; consequently, the particles in Glass A exhibit reduced movement.

Explanation:

Raising the temperature increases the solubility of solutes.

The experiment indicates that's glass B is at a higher temperature than glass A since the antacid dissolves more quickly in glass B than in glass A. Therefore, glass A must be cooler, leading to slower particle movement compared to glass B.

KiRa [2.9K]4 months ago
5 0

Answer:

D. The water in Glass A is at a lower temperature compared to that in Glass B, leading to a slower movement of particles in Glass A.

Explanation:

Temperature in scientific terms is characterized as the measurement of the average energy of motion of molecules within a substance. An increase in molecular speed indicates a rise in kinetic energy and subsequently, the temperature correspondingly increases.

As the solvent molecules gain speed, their interactions with solute particles increase, facilitating a quicker dissolution at elevated temperatures; this is in contrast to a scenario at decreased temperatures with slower molecular activity.

Consequently, the elevated temperature of the molecules in Glass B will contribute to a more rapid dissolution of the antacid compared to Glass A.

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