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Furkat
3 months ago
11

The position of a paddle on a waterwheel after t seconds is modeled by f(t) = 5.25 cosine (StartFraction pi Over 16 EndFraction

t minus pi). A positive function value indicates the paddle is above the waterline, while a negative value indicates the paddle is below the waterline.
What is the initial position of the paddle?

10.5 ft above the waterline
5.25 ft above the waterline
0 ft at the waterline
5.25 ft below the waterline

Mathematics
2 answers:
tester [12.3K]3 months ago
6 0

Answer:

5.25ft below the waterline

Step-by-step explanation:

1. I entered the given equation into a graphing calculator (I use Desmos) and substituted "t" with "x" since it’s easier that way.

2. A graph appeared. To find the initial position of the paddle, I checked where it was at t=0, which is the y-intercept. It shows it’s at -5.25, indicating it sits 5.25 below the surface of the water.

Leona [12.6K]3 months ago
5 0

Response:

D

Detailed explanation:

edge 2020

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Answer:

Attached is the question in consideration.

m\angle CEA =90 \ (deg)

m\angle BEF=135\ (deg)

\angle CEF forms a straight line.

\angle AEF depicts a right triangle.

The options 1,4,5,6 represent the correct answers.

Step-by-step explanation:

⇒ Given that \ ray\ AE  is ⊥FEC it constitutes a right triangle, leading to m\angle CEA =90\ (deg).

⇒ The measure for \angle BEF =135\ (deg) equals \angle BEF =\angle AEB +\angle AEF = (45+90)=135\ (deg) as \angle AEB bisects \angle AEC, implying that \angle AEB is half of \angle AEC, thus  \angle AEB = 45\ (deg).

⇒\angle CEF represents a straight line, as the angle measures across it yield 180\ (deg).

⇒ The angle measure for \angle AEF = 90\ (deg) is derived from the linear pair concept.

Since \angle CEA + \angle AEF = 180\ (deg), inserting the values of  m\angle CEA =90\ (deg) leads to \angle AEF = 90\ (deg).

The other two options are incorrect as:

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       it surpasses 180\ (deg) while \angle CEF is a               

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  • Also, m\angle CEB=2(m\angle CEA) is inaccurate.

     As \angle CEA = 90\ (deg) and \angle CEB=45\ (deg)

Thus, we have a total 4 valid answers.

The confirmed options are 1,4,5,6.

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