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leva
26 days ago
13

Given: NM ∥ XZ Prove: △XYZ ~ △NYM Triangles X Y Z and N Y M are shown. Triangle X Y Z is smaller and sits inside of triangle N Y

M, sharing part of 2 sides with triangle N Y M. The hypotenuses of both triangles are parallel. We know that side NM is to side XZ. If we consider side NY the transversal for these parallel lines, we create angle pairs. Using the , we can state that ∠YXZ is congruent to ∠YNM. We know that angle XYZ is congruent to angle by the reflexive property. Therefore, triangle XYZ is similar to triangle NYM by the similarity theorem.
Mathematics
1 answer:
lawyer [9.2K]26 days ago
7 0

Answer:

Parallel

corresponding angles theorem

NYM

AA

Step-by-step explanation:  I DID IT ON EDGE!: )

We know that side NM is  _________________

✔ parallel

to side XZ. If we consider side NY as the transversal, angle pairs are formed. According to the  _____________

✔ corresponding angles theorem

, it follows that ∠YXZ is congruent to ∠YNM. Also, angle XYZ is congruent to angle  _____________

✔ NYM

due to the reflexive property. Hence, triangle XYZ is similar to triangle NYM by the  _____________

✔ AA

 similarity theorem.

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We are given the triangle

△ABC, with m∠A=60° and m∠C=45°, and AB=8.

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Substituting the known values,

60° + m∠B + 45° = 180.

This gives us m∠B = 75°.

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Using the law of sines,

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We can substitute in the values.

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BC=\frac{8}{sin(45)} \times sin(60)

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Now we'll input the values.

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Calculating Perimeter:

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We substitute values here as well.

p=10.928+8+9.798

p=28.726

Calculating Area:

Using the area formula,

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we can then insert values.

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