answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
rosijanka
4 days ago
14

An electron is orbiting a nucleus which has a charge of 19e, under the action of the coulomb force at a radius of 1.15 × 10-10 m

. calculate the angular velocity of the electron, in radians per second.
Physics
2 answers:
Sav [1K]4 days ago
6 0

The angular velocity of an electron in its orbit around the nucleus, influenced by the Coulomb force, is \boxed{5.63\times10^{16}\text{ rad/sec}}.

Explanation:

Both the electron and the nucleus carry charges of opposite signs, leading to an attractive electrostatic force between them.

Despite this attraction, the electron continues to move in a circular trajectory around the nucleus. Its circular motion induces a centripetal force that prevents it from being pulled directly into the nucleus.

The equation representing the equilibrium of forces on the electron during its orbital path is shown as:

\boxed{F_c=F_e}...... (1)

The centripetal force acting on the electron can be defined as:

F_c=\dfrac{mv^2}{r}

In this formula, m represents the mass of the electron, v denotes the speed of the electron, and r is the radius of its circular path.

The electrostatic force exerted on the electron by the nucleus is expressed as:

F_e=\dfrac{1}{4\pi\epsilon_0}\dfrac{q_1q_2}{r^2}

Here, q_1\&q_2 represent the charges of the electron and nucleus, and r refers to the separation distance between the two charges.

The angular velocity of a body can be expressed as:

v=r\omega

In this instance, \omega signifies the angular velocity.

By substituting the values of centripetal force, electrostatic force, and angular velocity into equation (1), we obtain:

\dfrac{m\omega^2r^2}{r}=\dfrac{1}{4\pi\epsilon_0}\dfrac{q_1q_2}{r^2}

By plugging in the values into the previous expression, we get:

\omega^2=\dfrac{(9\times10^9)\times19(1.6\times10^{-19})\times(1.6\times10^{-19})}{(9.1\times10^{-31})\times(1.15\times10^{-10})^3}\\\omega^2=\dfrac{4.377\times10^{-27}}{1.38\times10^{-60}}\\\omega^2=3.17\times10^{33}\\\omega=5.63\times10^{16}\text{ rad/sec}

Thus, the angular velocity of the electron in its orbit around the nucleus, guided by the Coulomb force, is \boxed{5.63\times10^{16}\text{ rad/sec}}.

Learn More:

1. Learn about the threshold frequency of cesium

2. Understanding how a Na+ ion moves from inside the cell with an electric potential of -70 mV

3. What causes an electrical shock

Answer Details:

Grade: College

Subject: Physics

Chapter: Electrostatics

Keywords:

electron, orbiting, nucleus, coulomb force, radius of circular, attraction, centripetal force, angular velocity, rad/sec, charge, particles.

Maru [1K]4 days ago
3 0

Result: \omega = 13.41 \times10^{16}\ rad/sec

Detail:

Given that,

Charge   q = 19\times1.6\times 10^{-19} c

Radius r = 1.15\times 10^{-10}\ m

It is known that,

Centripetal force = Coulomb force

\dfrac{mv^{2}}{r} = \dfrac{1}{4\pi\epsilon_{0}}\times \dfrac{q_{1}q_{2}}{r^{2}}......(I)

Now, angular velocity

\omega = \dfrac{v}{r}

v = \omega\ r

Now, substitute the value of linear velocity in equation (I)

\dfrac{m\omega^{2}r^{2}}{r} = \dfrac{1}{4\pi\epsilon_{0}}\times \dfrac{q_{1}q_{2}}{r^{2}}

\omega^{2} = \dfrac{9\times10^{9}\times19\times1.6\times10^{-19}\times1.6\times10^{-19}}{1.6\times10^{-31}\times(1.15\times10^{-10})^{3}}

\omega ^{2} = 179.89\times 10^{32}\ rad/sec

\omega = 13.41\times 10^{16}\ rad/sec

Thus, this provides the necessary solution.


You might be interested in
A Honda Civic travels in a straight line along a road. The car’s distance x from a stop sign is given as a function of time t by
serg [1189]

a) Average velocity: 2.8 m/s

b) Average velocity: 5.2 m/s

c) Average velocity: 7.6 m/s

Explanation:

a)

The car's position over time t can be described by

x(t)=\alpha t^2 - \beta t^3

where

\alpha = 1.50 m/s^2

\beta = 0.05 m/s^3

To find the average velocity, we divide the displacement by the elapsed time:

v=\frac{\Delta x}{\Delta t}

At time t = 0, the position is:

x(0)=\alpha \cdot 0^2 - \beta \cdot 0^3 = 0

At time t = 2.00 s, the position is:

x(2)=\alpha \cdot 2^2 - \beta \cdot 2^3=5.6 m

This leads us to the displacement of

\Delta x = x(2)-x(0)=5.6-0=5.6 m

The duration for this interval is

\Delta t = 2.0 s - 0 s = 2.0 s

Therefore, the average velocity during this period is

v=\frac{5.6 m}{2.0 s}=2.8 m/s

b)

At time t = 0, the position is:

x(0)=\alpha \cdot 0^2 - \beta \cdot 0^3 = 0

At time t = 4.00 s, the position is:

x(4)=\alpha \cdot 4^2 - \beta \cdot 4^3=20.8 m

Thus, the displacement is

\Delta x = x(4)-x(0)=20.8-0=20.8 m

The time interval is

\Delta t = 4.0 - 0 = 4.0 s

This yields an average velocity of

v=\frac{20.8}{4.0}=5.2 m/s

c)

The position at t = 2 s is:

x(2)=\alpha \cdot 2^2 - \beta \cdot 2^3=5.6 m

And at t = 4 s it is:

x(4)=\alpha \cdot 4^2 - \beta \cdot 4^3=20.8 m

This gives us a displacement of

\Delta x = 20.8 - 5.6 = 15.2 m

While the time interval is

\Delta t = 4.0 - 2.0 = 2.0 s

So the resulting average velocity is

v=\frac{15.2}{2.0}=7.6 m/s

Find out more about average velocity:

6 0
9 days ago
Rosa studies the position-time graph of two race cars. A graph titled Position versus Time shows time in hours on the x axis, nu
Sav [1095]

Answer:

B. Truck X was ahead, not truck Y.

Explanation:

Let's analyze the information provided.

Truck X moved from the point (0,20) to (2.8,50). This indicates that it began at the 20th kilometer and reached 50 km in 2.8 hours. Thus, its speed is v1 = (s2 - s1) / t

v1 = (50 - 20) / 2.8

v1 = 10.7 km/h

Given that it started from the 20th km, it indeed had a head start. Since the line on the graph is linear, this shows its speed was constant without any change in direction.

On the other hand, Truck Y's movement went from the origin (0,0) to (5,20), meaning it took 5 hours to travel 20 km, resulting in a speed of v2 = 20 / 5

v2 = 4 km/h

Again, the straightness of its graph line signifies it maintained a constant speed in a single direction.

Thus, it is evident that Rosa erred in her assumption that Truck Y had a head start.

5 0
7 days ago
Read 2 more answers
Imagine you are a water molecule, carbon atom, or nitrogen atom that is inside a cow. Write a brief explanation of how you got f
Maru [1053]

Answer:

Explanation:

Each of the processes connected to these molecules varies.

For instance, water that has accumulated in the atmosphere returns to the ground as rain. Cows utilize this water from local water sources. This represents one method in which water transitions from the atmosphere to the cow's body.

Regarding carbon and nitrogen, the air inhaled by cows contains nitrogen, oxygen, carbon dioxide, and other gases. These molecules enter the cow through respiration.

6 0
2 days ago
A long cylindrical rod of diameter 200 mm with thermal conductivity of 0.5 W/m⋅K experiences uniform volumetric heat generation
Ostrovityanka [942]

Answer:

a, 71.8° C, 51° C

b, 191.8° C

Explanation:

Given the data:

D(i) = 200 mm

D(o) = 400 mm

q' = 24000 W/m³

k(r) = 0.5 W/m.K

k(s) = 4 W/m.K

k(h) = 25 W/m².K

The heat generation formula can be articulated as follows:

q = πr²Lq'

q = π. 0.1². L. 24000

q = 754L W/m

Thermal conduction resistance, R(cond) = 0.0276/L

Thermal conduction resistance, R(conv) = 0.0318/L

Applying the energy balance equation,

Energy In = Energy Out

This equates to q, which is 754L

From the initial analysis, the temperature at the interface between the rod and sleeve is found to be 71.8° C

Additionally, the outer surface temperature records as 51° C

Furthermore, based on the second analysis, the calculated temperature at the center of the rod is determined to be 191.8° C

6 0
9 hours ago
A book rests on the shelf of a bookcase. The reaction force to the force of gravity acting on the book is 1. The force of the sh
serg [1189]

Answer:

1. The force applied by the shelf supporting the book.

Explanation:

The free body diagram for the book is represented as follows:

1 - The weight of the book acting downward

2 - The normal force exerted by the shelf upward on the book.

As the book remains stationary, these two forces balance each other, and in accordance with Newton's Third Law, the reactive force equivalent to gravity is opposite and equal to the weight of the book. This reaction force prevents the book from falling off the shelf.

6 0
6 days ago
Read 2 more answers
Other questions:
  • A displacement vector points in a direction of θ = 23° left of the positive y-axis. The magnitude of this vector is D = 155 m. R
    12·1 answer
  • Three equal negative point charges are placed at three of the corners of a square of side d. What is the magnitude of the net el
    9·2 answers
  • Students work together during an experiment about Newton’s laws. The students use a setup that consists of a cart of known mass
    12·1 answer
  • Throughout the reflection, make sure you have a copy of the Student Guide, PDF or Word, and your data tables. Use the drop-down
    12·2 answers
  • Write a hypothesis about the effects of magnetic and electric fields. Use the format of "if . . . then . . . because . . ." and
    8·2 answers
  • A 600 kg car is at rest, and then accelerates to 5 m/s.
    10·1 answer
  • Two loudspeakers 42.0 m apart and facing each other emit identical 115 Hz sinusoidal sound waves in a room where the sound speed
    5·1 answer
  • Imagine you derive the following expression by analyzing the physics of a particular system: a=gsinθ−μkgcosθ, where g=9.80meter/
    6·1 answer
  • A dipole of moment 0.5 e·nm is placed in a uniform electric field with a magnitude of 8 times 104 N/C. What is the magnitude of
    11·1 answer
  • The position of a particle is r⃗ (t)=(3.0t2iˆ+5.0jˆ−6.0tkˆ)m. (a) Determine its velocity and acceleration as functions of time.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!