A baseball of mass m = 0.49 kg is dropped from a height h1 = 2.25 m. It bounces from the concrete below and returns to a final h

This is somewhat misleading, and I encountered the same question in my homework. An electric field strength of 1*10^5 N/C is provided, along with a drag force of 7.25*10^-11 N, and the critical detail is that it maintains a constant velocity, indicating that the particle is in equilibrium and not accelerating.
<span>To solve, utilize F=(K*Q1*Q2)/r^2 </span>
<span>You'll want to equate F with the drag force, where the electric field strength translates to (K*Q2)/r^2; substituting the values results in </span>
<span>(7.25*10^-11 N) = (1*10^5 N/C)*Q1 ---> Q1 = 7.25*10^-16 C </span>

As the parachutist is descending at a steady rate

we can conclude that

Acceleration indicates the change in velocity

given the constant velocity in this scenario

Thus, in this situation, we find the acceleration to be zero

It’s understood from Newton's second law

where a is equal to 0

Here, the force due to gravity

equals the force due to buoyancy

Hence, we can deduce

therefore

as such the upward force is counteracted by the downward force.

For a string that is secured at both ends, the oscillation amplitude must be zero at both extremities of the string. Refer to the attached images for clarity. It is evident that our fundamental harmonic will have the following wavelength: All subsequent harmonics are simply multiples of the fundamental. The three longest wavelengths are as follows:

Answer:

Cl2 concentration: 1,048 ppm

Explanation:

Molarity (M) is a unit that indicates how many moles of a substance are in one liter of solution, while ppm is similar to mg/L, representing the mass of the substance per liter. To convert M to ppm, we need to consider both mass and volume. The volume remains in liters in both cases, so no adjustments are needed there. The challenge arises when converting moles from molarity to milligrams for the mg/L conversion to find ppm.

First, we must recognize that the substance in question is Cl2, prompting the need to connect mole quantity to its mass. Referring to the periodic table, we find the atomic weight of Cl is 35.4 g/mole. This relationship allows us to establish moles' mass, as shown in the following equation:

We already know the moles of Cl2 in the solution is (moles=2.96x10^-5). Substituting this value, we can calculate:

Keep in mind that we're discussing the mass found per liter of solution, which gives us 1.048x10^-3 g/L. We previously established that ppm equals mg/L, so we need to convert grams to milligrams:

1 g = 1000 mg

Now multiplying both sides by 1.048x10^-3:

1 * 1.048x10^-3 g = 1000 * 1.048x10^-3 mg

Thus, 1,048x10^-3 g translates to 1,048 mg.

This amount of mass detected in one liter indicates that the concentration of the substance in the solution is:

1,048 mg/L

Since we know that mg/L=ppm, the conclusion is:

1,048 ppm

Answer:

29.4 N/m

0.1

Explanation:

a) The restoring force is described by: F_r = -k*x.

The gravitational force is given as: F_g = mg.

Where:

F_r = restoring force,

F_g = gravitational force,

g represents acceleration due to gravity,

and k is the force constant, while x1 and x2 are the displacements for the two masses.

Given:

m1 = 1.29 kg,

m2 = 0.3 kg,

x1 = -0.75 m,

x2 = -0.2 m,

g = 9.8 m/s².

Substituting the information yields:

F_r = F_g

-k*x1 + k*x2 = m1*g - m2*g.

Solving gives k = 29.4 N/m.

b) To find the unloaded length l:

l = x1 - (F_1/k).

Given:

m1 = 1.95kg, x1 = -0.75m.

Substituting in provides:

l = x1 - (F_1/k) = 0.1.