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strojnjashka
3 months ago
10

Two atoms collide while moving in a dilute gas. The larger atom has a mass M1 = 6 Daltons and a speed v1 = 200 m/s, while the sm

aller has a mass M2 = 1 Daltons. During the collision both atoms simply bounce off each other. They do not change their speeds, but after the collision they each change their directions, bouncing in the indicated directions. (You may express your results using the mass unit "Daltons". 1 Dalton is approximately equal to the mass of a proton or neutron and is defined as one-twelfth the mass of a single neutral carbon-12 atom in its ground state.)
A. What is the magnitude of the change in the momentum, Δp1, of mass M1?
B. What is the change in the total momentum of the pair?
C. What is the magnitude of the change in the momentum Δp2, of mass M2?
Physics
1 answer:
ValentinkaMS [3.4K]3 months ago
8 0

Answer:

a). ΔP1=-2.4 x10^{3} \frac{D*m}{s}

b). Pp=0 F=0

c). ΔP2=2.4 x10^{3} \frac{D*m}{s}

Explanation:

Initial momentum

P_{1}=m_{1}*v_{i1}

Final momentum

P_{1f}=m_{1}*v_{f1}=-m_{1}*v_{i1}

The change of momentum m1 is:

a).

ΔP1=P_{1f}-P_{1}

ΔP1=-m_{1}*v_{i1}-m_{1}*v_{i1}

ΔP1=-2*m_{1}*v_{i1}

ΔP1=-2*6 D*200\frac{m}{s}

ΔP1=-2.4x10^{3}\frac{D*m}{s}

b).

According to the conservation of energy principle, without external forces, the momentum change for the pair equals zero

P=0

Fx=0

c).

ΔP1+ΔP2=0

ΔP2=-ΔP1

ΔP2=--2.4x10^{3}\frac{D*m}{s}

ΔP2=2.4x10^{3}\frac{D*m}{s}

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A ball collides elastically with an immovable wall fixed to the earth’s surface. Which statement is false? 1. The ball's speed i
Maru [3345]

Answer:

Statements 4, 6 & 7 are incorrect.

Explanation:

In any elastic collision, the overall momentum vector sum of the system remains zero.

In this scenario, an elastic collision occurs between the ball and a stationary wall. The ball's velocity will consistently revert after the impact, leading to a change in direction of momentum.

The initial momentum of the ball is represented as:

p=m.v

where:

m = mass of the ball

v = initial velocity of the body

post-collision for the elastic interaction:

p=m.(-v)

  • Here, the momentum changes solely in direction, thus contradicting statement 7.
  • During the impact, both the ball and the wall exert forces on each other that are equal and opposite. The wall remains motionless, while the ball is influenced by the wall's reaction force, performing work on it, which contradicts statement 4.
  • Given that this collision is elastic, the ball's form and dimensions do not alter.
  • The previous points clearly indicate that not all provided statements hold true, thus violating statement 6.
4 0
3 months ago
If a metal wire is 4m long and a force of 5000n causes it to stretch by 1mm, what is the strain?
serg [3582]

Answer:

2.5\cdot 10^{-4}

Explanation:

Strain is defined as the ratio of an object's dimensional change when subjected to a force:

S=\frac{\Delta L}{L_0}

where

\Delta L indicates the alteration in length of the object

L_0 signifies the object's initial length

In this case, we have L_0 = 4 m and \Delta L=1 mm=0.001 m, hence the strain is

S=\frac{\Delta L}{L_0}=\frac{0.001 m}{4 m}=2.5\cdot 10^{-4}


5 0
2 months ago
An airplane flies with a velocity of 55.0 m/s [35o N of W] with respect to the air (this is known as air speed). If the velocity
ValentinkaMS [3465]
V - wind speed;
53° - 35° = 18°
v² = 55² + 40² - 2 · 55 · 40 · cos 18°
v² = 3025 + 1600 - 2 · 55 · 40 · 0.951
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v = √440.6
v = 20.99 ≈ 21 m/s
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5 0
2 months ago
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