M1V1 = M2V2
(2.50)(100.0) = (0.550)V2
V2 = 455mL
From 100.0 mL of 2.50 M KBr, you can prepare 455 mL of 0.550 M solution.
A total of 1.505×10^23 lead atoms
In the lungs, the volume of lead equals the total lung volume, which is 5.60L
1 mole corresponds to 22.4L
Thus, 5.6L of lead converts to 5.6/22.4 = 0.25 moles
According to Avogadro's law
1 mole of lead contains 6.02×10^23 lead atoms
Thus, 0.25 moles of lead equates to 0.25×6.02×10^23 = 1.505×10^23 lead atoms
<span>Salts result from the reaction between bases and water. - FALSE
</span><span>Most salts are ionic and dissolve in water. - TRUE
</span><span>Most salts are not dissolved in water and do not have electrical charges. - FALSE
</span><span>Solutions containing salt and water are unable to conduct electricity. - FALSE
:)</span>
Response:
2200 mg of antibiotic
Explanation:
The prescribed antibiotic dosage is 40 mg/kg of body weight.
For a patient weighing 55 kg, we calculate the dose of antibiotic as follows:
If we analyze 40/1000000, we can determine antibiotic allocation in kg per kg of weight
= 0.00004 kg of antibiotic for each kilogram
0.00004 multiplied by 55 (to find out the required amount for a 55 kg individual)
= 0.0022 kg
This 0.0022 figure converts to milligrams as follows
0.0022*10^6
= 2200 mg of antibiotic is indicated for a patient weighing 55 kg.
The response to this inquiry involves energy release. The bonds holding molecule atoms act as energy reserves. One method of energy release occurs when these bonds are severed, allowing energy to disperse outward. This breaking leads to smaller molecules rather than the creation of a larger one.
