Answer:
The empirical formula is: C₂H₃O
Explanation:
The empirical formula, often referred to as the “minimum formula,” provides the simplest way to represent a chemical compound, illustrating both the present elements and their minimum integer ratios in terms of atoms.
The mass percentage composition indicates the proportion by mass of each element in a compound.
Using 100 g of the compound as a reference, the percentage can be expressed in grams. Thus, presuming 100 g of the compound consists of 53.46 g of C, 6.98 g of H, and 39.56 g of O.
Considering the molecular masses of each component, one can derive the number of relative atoms for each element:
C: 
H:
O:
Subsequently, divide each value by the smallest one:
C: 
H:
O:
Approximating decimals to the nearest integer gives:
C: 2
H: 3
O: 1
Therefore the empirical formula is: C₂H₃O
Answer:
CaS, CaBr₂, VBr₅, and V₂S₅.
Explanation:
- The ionic compound must exhibit neutrality; its total charge should equal zero.
- A binary ionic compound is formed from two distinct ions.
Ca²⁺ combines with either Br⁻ or S²⁻ to create binary ionic compounds.
- CaS is created when Ca²⁺ pairs with S²⁻ resulting in the neutral binary ionic compound CaS.
- CaBr₂ results from the combination of one mole of Ca²⁺ with two moles of Br⁻ to form the neutral binary ionic compound CaBr₂.
V⁵⁺ can also unite with either Br⁻ or S²⁻ to produce binary ionic compounds.
- V₂S₅ is formed when two moles of V⁵⁺ bond with five moles of S²⁻ yielding the neutral binary ionic compound V₂S₅.
- VBr₅ is produced by combining one mole of V⁵⁺ with five moles of Br⁻ to form the neutral binary ionic compound VBr₅.
Thus, the empirical formulas for four binary ionic compounds that may be produced are: CaS, CaBr₂, VBr₅, and V₂S₅.
Answer:
Positron emission
Explanation:
In positron emission, a proton transforms into a neutron. This alteration results in a daughter nucleus with its mass number increased by 1, while the atomic number remains unchanged. The formation of a new neutron boosts the neutron count in the daughter nucleus, thus enhancing the N/P ratio.
Concurrently, a positron is emitted along with an anti-neutrino to ensure spin conservation.
To determine the length of each side,
employ the distance formula represented by the equation:
Distance = ((x2-x1)^2+(y2-y1)^2)^0.5
Calculating
<span>AB = 8 units BC = 6 units AC = 10 units
</span><span>MN =8units NO = 6 units MO = 10 units
</span><span>XY = 6.32 units YZ = 6.32 units XZ = 8.94 units
</span>JK = 4.47 units KL = 4.47 units JL = 6 units
1 The correct response is option b) triangles ABC and MNO are Congruent. <span>These triangles, ABC and MNO, have congruent side lengths.
</span>2 The answer is option c) rotation.
There is a rotation of 90º around the origin for triangles ABC and MNO, where B=N,
B=N
C----------O
A----------M
