What volume of 0.550 M KBr solution can you make from 100.0 mL of 2.50 M KBr?

Answer:

The equilibrium state is established at the fourth panel.

Explanation:

Chemical Equilibrium signifies that the overall characteristics of the system seem to stabilize and stop fluctuating.

However, in terms of chemical equilibrium, this should accurately be described as dynamic equilibrium, where the rates of the forward and backward reactions are balanced, even though the concentrations may still adjust.

Equilibrium occurs when the composition of spheres in the specific panel matches that in the adjacent panels, where the particular color and quantity of spheres become invariant.

Based on the question's illustration,

- The first panel displays ten large red spheres.

- The second panel shows 8 large red spheres and two small blue spheres.

- The third panel depicts six large red spheres and four small blue spheres.

- The fourth panel illustrates four large red spheres and six small blue spheres.

- The fifth panel features four large red spheres and six small blue spheres.

Clearly, the composition of the spheres remains constant from the fourth to the fifth panel. Hence, the first appearance of this stable arrangement is in the fourth panel.

Therefore, equilibrium is achieved for the first time at the fourth panel.

Hope this Helps!!!

Answer: a) Cathode(-): b) Anode(+): b) 0.640 grams of Ba will be deposited. Explanation: a) The problem is framed around Faraday's law of electrolysis, where molten barium chloride contains Ba^2+ and Cl^- ions. The reduction occurs at the cathode, while oxidation occurs at the anode. b) The inquiry relates to the potential mass of barium metal generated when a 0.50 ampere current is supplied for 30 minutes. 1 mole of Ba is deposited with the transfer of 2 moles of electrons, with each mole of electron equating to one Faraday (96485 Coulomb). Thus, 192970 C is required for the deposition of 1 mole of Ba. Total available charge can be calculated via the equation q=i*t; here, it results in 900 C, leading us to find 0.00466 mole of Ba from these coulombs. Converting the moles of Ba to grams gives us 0.640 g Ba deposited after 0.50 A over 30 minutes.

To determine the least degree of precision, we must base it on the mass of 4.05 kg or two decimal places. Thus, we add 0.56795 kg (0.57 kg) and 0.1001 kg (0.1 kg), resulting in a total of 4.72 kg.

<span>Conversely, to find the greatest degree of precision, we convert 4.05 kg into grams, which gives us 4050 g. Therefore, summing 4050 g with 567.95 g and 100.1 g yields 4718.05 grams, which rounds to 4718 g.</span>

Answer:

78.96 g of NaC2H3O2

Explanation:

The following information is provided:

• The solution's volume is 350 mL
• The solution's molarity is 2.75 M
• The molar mass of NaC2H3O2 is 82.04 g/mol

We need to find the mass of the solute:

First, we calculate the number of moles:

Moles = Molarity × Volume

Thus;

Moles of solute = 2.75 M × 0.350 L

                        = 0.9625 moles

Next, we find the mass:

Mass = Moles × Molar mass

        = 0.9625 moles × 82.04 g/mol

        = 78.9635 g

      = 78.96 g

Therefore, the amount of NaC2H3O2 required is 78.96 g

The resulting temperature, following the change in volume and pressure, is -27.26°C. To find this temperature, we apply the combined gas law equation—a formulation where initial and final pressures, volumes, and temperatures are compared. Given the initial conditions and transformations, when we input the stipulated values, we reach the conclusion that the resultant temperature is -27.26°C.