Answer:
3.816 × 10⁻³ M
Explanation:
A stock solution of Cu²⁺(aq) is made by dissolving 0.8875 g of solid Cu(NO₃)₂∙2.5H₂O in a 100.0-mL volumetric flask, and then brought up to volume with water. What is the molarity (in M) of Cu²⁺(aq) in this stock solution?
We can derive the following relations:
- The molar mass of Cu(NO₃)₂∙2.5H₂O is 232.59 g/mol.
- Each mole of Cu(NO₃)₂∙2.5H₂O yields one mole of Cu²⁺.
The moles of Cu²⁺ present in 0.8875 g of Cu(NO₃)₂∙2.5H₂O are:

The molarity of Cu²⁺ is:

Answer:
The process of converting glucose to glucose-6-phosphate is an endergonic reaction, which is coupled with the exergonic hydrolysis of ATP.
Explanation:
Within glycolysis, the phosphorylation of glucose to glucose-6-phosphate occurs first, facilitated by the hexokinase enzyme. This reaction is endergonic. This phosphorylation is a coupled reaction tied to ATP hydrolysis, where the free energy released by ATP hydrolysis drives glucose phosphorylation.
The response is:
No, the equation is not balanced. Neither the Nitrogen (N) nor the Hydrogen (H) are in balance!
Here's the reasoning:
⓵ A properly balanced chemical equation means that the quantity of atoms on the reactants side matches that on the products side.
→ The equation lacks balance because there are 2 Nitrogen atoms and 2 Hydrogen atoms on the reactants side. In contrast, on the products side, there is only 1 Nitrogen atom and 4 Hydrogen atoms. Thus, the number of atoms on each side is not consistent!
Hopefully, this clarification is helpful; feel free to reach out if you have any further questions! ☻
The accompanying illustration depicts the structure of dimethyl terephthalate. Explanation: Dimethyl terephthalate, whose chemical formula is C6H4 (COOCH3) 2, is a diester derived from terephthalic acid and methanol. It appears as a white solid. Another method of syntheses involves p-xylene and methanol, characterized by an oxidation process followed by esterification.
The reaction that exhibits the lowest K value is:
A + B → 2 C; E°cell = -0.030 V.
This can be rationalized by noting that the standard electrode potential of the cell is directly proportional to the reaction's equilibrium constant. A higher potential results in a larger K value, whereas a lower potential yields a smaller K value.