The essential principle for this question is Ohm’s Law: V=IR, I=V/R, R=V/I. Therefore, the answer is (3) Resistance, as it is inversely related to Current (I=V/R).
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Speed is defined as distance over time. Hence, to determine the distance, we use d = V * t. Plugging in the values yields d = (72 Km / h) * (1h / 3600s) * (4.0 s) = 0.08Km. Thus, during this distracted period, a distance of 0.08Km was covered.
Answer:The tension on either side of the cable is 3677.57 N
Explanation:
given data
traffic light = 20 kg
cable spanning between two poles = 30 m
sag of the cable = 0.40 m
solution
through the free body diagram
tan θ =
.............1
θ = 1.527 °
and
tension = mg
The horizontal net force can be stated as
T2 cosθ = T1 cosθ.................2
and
thus T2 - T1..............3
and
in the vertical axis we express as
( T1 + T2) sinθ = mg...................4
therefore using equation 3 here
2 × T1 sin(1.527) = 20 × 9.8
T1 = 3677.57 N