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mariarad
1 month ago
7

The probability that a randomly selected person has high blood pressure (the event H) is P(H) = 0.3 and the probability that a r

andomly selected person is a runner (the event R) is P(R) = 0.4. The probability that a randomly selected person has high blood pressure and is a runner is 0.2. Find the probability that a randomly selected person is a runner, given that he has high blood pressure.
Mathematics
1 answer:
Svet_ta [12.7K]1 month ago
4 0

Answer:

The likelihood of selecting an individual with high blood pressure who is also a runner is 2/3.

Step-by-step explanation:

Based on the data provided:

P( Choosing someone with high blood pressure )  =  0.3

or stated as P(H)  = 0.3

P( Choosing a runner )  =  0.4

or stated as P(R)  = 0.4

Now, P( Selecting a person with high blood pressure as well as being a runner)  = 0.2

⇒ P(H∩ R)  = 0.2

Next, we want to calculate the P(the selected individual is a runner, given they have high blood pressure)

which means we need to determine: P(R/H)

Using BAYES THEOREM:

P(R/H) = \frac{P(R\cap H)}{P(H)}

\implies P(R/H) = \frac{0.2}{0.3 } = \frac{2}{3}

So, the chance of choosing a person with high blood pressure who is a runner stands at 2/3.

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