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Effectus
3 days ago
6

A rocket has a mass 250 x (10^3) slugs on earth. Specify(a) its mass in SI units, and(b)its weight in SI units.If the rocket is

on the moon where the acceleration due to gravity is gm=5.30ft/s2, determine to three significant figures (c) its weight in SI units, and (d) its mass in SI units.
Physics
1 answer:
Yuliya22 [1.1K]3 days ago
8 0

Explanation:

We are given that,

Mass of the rocket, m=250\times 10^3\ slugs

(a) The standard unit of mass is kilogram (kg). The conversion between slugs and kilograms is as follows:

1 slug = 14.59 kg

Thus, 250\times 10^3\ slugs=250\times 10^3\times 14.59

Mass of the rocket, m = 3647500 kg

(b) The weight of the rocket can be expressed as:

W = m g

W=3647500\times 9.8=35745500\ N

or

W=3.5\times 10^7\ N

(c) If the rocket were on the moon, the gravitational acceleration on the moon is given as a=5.3\ ft/s^2=1.61\ m/s^2

Mass refers to the quantity of matter present in an object. Therefore, the mass of the rocket remains constant at 3647500 kg

The weight of the rocket on the moon would be, W=mg

W=3647500\times 1.61

W = 5872475 N

or

W=5.8\times 10^6\ N

Thus, this is the final answer required.

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Complete Question

An aluminum "12 gauge" wire measures a diameter of 0.205 centimeters. The resistivity ρ of aluminum is 2.75×10−8 ohm-meters. The electric field E in the wire varies over time as E(t)=0.0004t2−0.0001t+0.0004 newtons per coulomb, where time is recorded in seconds.

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     The radius of the wire is  r = \frac{0.00205}{2} = 0.001025 \ m

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      Q = 120 \int\limits^{t}_{0} { [ 0.0004t^2 - 0.0001t +0.0004] } \, dt

     Q = 120 [ \frac{0.0004t^3 }{3} - \frac{0.0001 t^2}{2} +0.0004t] } \left | t} \atop {0}} \right.

The question states that t =  5 seconds

           Q = 120 [ \frac{0.0004t^3 }{3} - \frac{0.0001 t^2}{2} +0.0004t] } \left | 5} \atop {0}} \right.

          Q = 120 [ \frac{0.0004(5)^3 }{3} - \frac{0.0001 (5)^2}{2} +0.0004(5)] }

         Q =2.094 C

     

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