Answer:
160/1001, 175/1001
Step-by-step explanation:
i) We calculate:
₈C₁ methods to select 1 new camera from a selection of 8
₆C₃ methods to select 3 refurbished cameras from a selection of 8
₁₄C₄ methods to select 4 cameras from the total of 14 cameras
The probability formula is:
P = ₈C₁ ₆C₃ / ₁₄C₄
P = 8×20 / 1001
P = 160 / 1001
P ≈ 0.160
ii) For at most one new camera, it means we want either one new camera or none at all. We've calculated the probability of selecting one new camera already. The probability of not selecting any new camera is equivalent to selecting 4 refurbished cameras:
P = ₆C₄ / ₁₄C₄
P = 15 / 1001
Therefore, the combined probability is:
P = 160/1001 + 15/1001
P = 175/1001
P ≈ 0.175
La respuesta es 4,13 al problema.
The provided function is:
P = 0.04x + 0.05y + 0.06(16-x-y)
To determine the function's value at each vertex, simply plug in the respective x and y coordinates into the equation to find the value of P as shown below:
1- For (8,1):
P = 0.04x + 0.05y + 0.06(16-x-y)
P = 0.04(8) + 0.05(1) + 0.06(16-8-1)
P = 0.79
2- For (14,1):
P = 0.04x + 0.05y + 0.06(16-x-y)
P = 0.04(14) + 0.05(1) + 0.06(16-14-1)
P = 0.67
3- For (3,6):
P = 0.04x + 0.05y + 0.06(16-x-y)
P = 0.04(3) + 0.05(6) + 0.06(16-3-6)
P = 0.84
4- For (5,10):
P = 0.04x + 0.05y + 0.06(16-x-y)
P = 0.04(5) + 0.05(10) + 0.06(16-5-10)
P = 0.76
I hope this is useful:)
The question requires completion since the inventory data is absent.
