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IRISSAK
2 days ago
10

A gas at 928 kpa, 129 C occupies a volume of 569 L. Calculate the volume at 319 kpa and 32 C.

Chemistry
1 answer:
VMariaS [1K]2 days ago
4 0

Answer:

1255.4L

Explanation:

Parameters given:

P₁  = 928kpa

T₁  = 129°C

V₁  = 569L

P₂ = 319kpa

T₂  = 32°C

To find:

V₂  =?

Solution:

We will apply the combined gas law to address this issue. The formula is as follows:

           \frac{P_{1} V_{1} }{T_{1} } = \frac{P_{2} V_{2} }{T_{2} }

P, V and T represent pressure, volume, and temperature, respectively

The subscripts 1 and 2 indicate the initial and final conditions.

Next,

 convert the units appropriately;

             kpa to atm,  °C to K

P₂ = 319kpa converts to 3.15atm

P₁  = 928kpa converts to 9.16atm

T₂  = 32°C converts to 305K (273 + 32)

T₁  = 129°C converts to 402K (129 + 273)

Insert the values into the equation and determine V₂;

        \frac{9.16 x 569}{402} = \frac{3.15 x V_{2} }{305}

       V₂   = 1255.4L

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Calculate the molarity of 48.0 mL of 6.00 M H2SO4 diluted to 0.250 L
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Answer:

The molality is 1.15 m.

Molality is calculated by dividing the number of moles of solute by the kilograms of solvent, which in this case is water.

Calculate moles of H₂SO₄ from molarity:

C = n/V → n = C × V = 6.00 mol/L × 0.048 L = 0.288 moles

Mass of solvent (water) based on density:

m = ρ × V = 1.00 kg/L × 0.250 L = 0.250 kg

Therefore, molality is:

m = moles/solvent mass = 0.288 moles / 0.250 kg = 1.15 m

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14 days ago
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Why is it important to have regular supervision of the weight and measurements in the market
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Answer:

Oversight of weights and measures ensures correct evaluations of goods and services so that everyone receives a fair exchange in the marketplace. It also acts as a deterrent, promoting honesty among traders.

Explanation:

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15 days ago
When performing a flame test using the method described in the manual, you complete the flame test of KNO3 and find a yellow col
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Answer:

The nichrome wire has contaminants.

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The testing solution could also be contaminated, causing it to display a color different from the anticipated shade of the test ion.

7 0
10 days ago
The volume of a gas at 6.0 atm is 2.5 L. What is the volume of the gas at 7.5 atm at the same temperature?
castortr0y [923]

Greetings!

The result is:

The new volume is: 2L

Rationale:

Because the temperature remains constant, we can apply Boyle's Law to solve this issue.

Boyle's Law stipulates that:

P_{1}V_{1}=P_{2}V_{2}

Where,

P is the gas's pressure.

V is the gas's volume.

According to the information provided:

V_{1}=2.5L\\P_{1}=6.0atm\\P_{2}=7.5atm

Let's put the values into the equation:

2.5L*6.0atm=7.5atm*V_{2}

2.5L*6.0atm=7.5atm*V_{2}\\\\V_{2}=\frac{2.5L*6.0atm}{7.5atm}=\frac{15L.atm}{7.5atm}=2L

Consequently, the new volume is: 2L

Wishing you a lovely day!

7 0
2 days ago
Find the age t of a sample, if the total mass of carbon in the sample is mc, the activity of the sample is a, the current ratio
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Hence, we have N = N₀e - λt, which is the equation for radioactive decay. Rearranging gives us N₀/N = e λt, or In(N₀/N) = - λt, which becomes equation 1.
The sample contains mc kg of carbon, leading to an activity measured as A/mc decay per kg. The variable r represents the initial mass of C-14 in the sample at t=0 relative to the total mass of carbon which is calculated as [(total number of C-14 atoms at t = 0) × ma] / total mass of carbon. Thus, N₀ equates to r/ma, which becomes equation 2.
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