A gas at 928 kpa, 129 C occupies a volume of 569 L. Calculate the volume at 319 kpa and 32 C.
1 answer:
Answer:
1255.4L
Explanation:
Parameters given:
P₁ = 928kpa
T₁ = 129°C
V₁ = 569L
P₂ = 319kpa
T₂ = 32°C
To find:
V₂ =?
Solution:
We will apply the combined gas law to address this issue. The formula is as follows:
P, V and T represent pressure, volume, and temperature, respectively
The subscripts 1 and 2 indicate the initial and final conditions.
Next,
convert the units appropriately;
kpa to atm, °C to K
P₂ = 319kpa converts to 3.15atm
P₁ = 928kpa converts to 9.16atm
T₂ = 32°C converts to 305K (273 + 32)
T₁ = 129°C converts to 402K (129 + 273)
Insert the values into the equation and determine V₂;
V₂ = 1255.4L
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Answer:
The temperature of a vessel at a pressure reading of 1.250 atm is 296.43 K.
Explanation:
At standard temperature and pressure (STP), the temperature is valued at 273.15 K with a pressure of 1.000 atm.
If the pressure is measured as 1.250 atm at temperature T.
Applying Gay Lussac's law:
(When volume is constant)
At a pressure of 1.250 atm, the temperature of the vessel is 296.43 K.