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Juli2301
4 months ago
10

A liquid has a volume of 34.6 ml and a mass of 46.0 g. what is the density of the liquid?

Chemistry
1 answer:
Anarel [2.9K]4 months ago
5 0

To find the density of a material, divide its mass by its volume:

density = mass ÷ volume

 

Given mass and volume values, calculate the density as follows:

density = 46.0 grams ÷ 34.6 milliliters

density = 1.33 grams per milliliter

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An atom of beryllium (m = 8.00 u) splits into two atoms of helium (m = 4.00 u) with the release of 92.2 kev of energy. if the or
VMariaS [2998]
The energy released results in a kinetic energy of 92.2 keV for the products. We should convert keV into Joules, noting that 1 keV equals a kiloelectron volt. The required conversion is: 1.602×10⁻¹⁹ <span>joule = 1 eV

Kinetic energy = 92.2 keV * (1,000 eV/1 keV) * (</span>1.602×10⁻¹⁹ joule/1 eV) = 5.76×10²³ Joules

Next, we can determine the velocity of each He atom from the kinetic energy:
KE = 1/2*mv²
5.76×10²³ Joules = 1/2*(4)(v²)
This solves to give us: v = 5.367×10¹¹ m/s
4 0
2 months ago
Read 2 more answers
Two atoms bonded together will remain some distance apart, minimizing the Question 1 options: A) potential energy of the bond. B
Anarel [2989]

Answer:

1) potential energy within the bond.

2) Linear

3) Electrons are transferred from K to Cl.

4) ClF

5) Oxygen

6) Electrolysis

7) Double displacement

Explanation:

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8 0
2 months ago
The volume of the ideal gas in the container is 9 m3. What would the volume be if four more blocks were placed on top of the lid
castortr0y [3046]
Response:
             4.5 m³

Resolution:
              The statement indicates the presence of two blocks on a lid of a container with a volume of 9 m³. The lid's weight is equal to that of the two blocks. Thus, there were initially four blocks (or 4 atm pressure) acting on a volume of 9 m³.

After adding four additional blocks on the lid, the pressure rises from 4 atm to 8 atm (2 atm from the lid, 2 atm from the original blocks, and 4 atm from the new blocks).

Hence, The data established is,

                  P₁  =  4 atm

                  V₁  =  9 m³

                  P₂  =  8 atm

                  V₂  =?

Using Boyle's Law,

                               P₁ V₁  =  P₂ V₂

Resolving for V₂,
                               V₂  =  P₁ V₁ / P₂

Substituting values yields:
                               V₂  =  (4 atm × 9 m³) ÷ 8 atm

                               V₂  =  4.5 m³
0 0
3 months ago
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