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18 days ago

Which element can form a chloride with a general formula of MCl2 or MCl3

1 answer:

5 0

The oxidation state numbercan aid in identifying the unknown element present in both compounds. They denote the number of electrons that are either donated, received, or shared to yield compounds.

Remember the fundamental principles governing oxidation numbers.

1. In a neutral compound, the total of all oxidation numbers is zero.
2. Chlorine, bromine, and iodine typically exhibit an oxidation number of -1(unless paired with fluorine and oxygen)

Assume the oxidation state for element Mis designated as x.
Referring to rule 2, chlorine possesses an oxidation state of -1.

Now, for the compound MCl₂ (which is neutral), the equation can be formulated as
x + (2 * -1)= 0 ⇒ x₁= +2

For MCl₃, the corresponding equation is
x + (3 * -1)= 0 ⇒ x₂= +3

This indicates that the elementhas two distinct oxidation statesin its compounds, which are +2and +3.

The identified element is iron (Fe), as it shows +2 and +3 oxidation states across these compounds.

Memorizing this is essential. Regrettably, there isn't a simpler method to tackle these oxidation states.

The final answer is iron (Fe).

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Two mixtures were prepared from three very narrow molar mass distribution polystyrene samples with molar masses of 10,000, 30,00

alisha [2865]

Answer:

Some components of your question seem to be missing.

We created two mixtures from three polystyrene samples with very narrow molar mass distributions, which are 10,000, 30,000, and 100,000 g mol−1, as outlined below: (a) Equal molecule counts of each sample (b) Equal sample masses (c) Mixing the two samples with molar masses of 10,000 and 100,000 g mol−1 in a mass ratio of 0.145:0.855. For each mixture, compute the number-average and weight-average molar masses and interpret the significance of these values.

Answers:

a) 46,666.66 g/mol

b) 20,930.23 g/mol

c) 43,333.33 g/mol

Explanation:

A) For equal numbers of molecules from each sample, we use $Mn = \frac{n(M1 + M2 + M3)}{3n}$

to determine equal molecule counts: n1 = n2 = n3 = n.

The resulting Mn = 46,666.66 g/mol.

B) To ascertain equal masses of each sample, we apply the following formula:

$Mn = \frac{W1 + W2 +W3}{\frac{W1}{M1} +\frac{W2}{M2}+ \frac{W3}{M3} }$

THE REMAINING PORTION OF THE SOLUTION IS ATTACHED BELOW

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28 days ago

Determine the number of bonding electrons and the number of nonbonding electrons in the structure of cs2.

lorasvet [2668]

Carbon disulfide (S=C=S) consists of a single carbon atom and two sulfur atoms. Carbon possesses 4 valence electrons, whereas sulfur has 6. In the bonding process, all four valence electrons from carbon participate, while each sulfur atom provides two electrons for bonding. Consequently, a total of 4 + 2(2) = 8 electrons are involved in bonding, while there are 8 electrons (four from each sulfur atom) that remain unbonded.

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11 days ago

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A 2 L bottle containing only air is sealed at a temperature of 22°C and a pressure of 0.982 atm. The bottle is placed in a freez

Anarel [2728]

The answer is.997 atm. 1. Identify the combined gas law equation... (P1V1/T1 = P2V2/T2) 2. Gather our values... P1=.982 atm P2=? (this is what we want to find) V1= 2 L V2= 1.8 L T1= 22 C = 295 K T2= -3 C = 270 K - Note: Always convert to Kelvin. To do this, add 273 to the Celsius value. 3. Rearranging the formula to suit this problem... (P2=P1V1T2/V2T1) 4. Insert our values... P2=.982 atm x 2 L x 270 K / 1.8 L x 295 K 5. Calculate and the result should yield....997 atm - If you require further clarification or assistance, feel free to reach out and I'll be happy to help!

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19 days ago

A chemist combined chloroform (CHCl3) and acetone (C3H6O) to create a solution where the mole fraction of chloroform is 0.187. T

KiRa [2853]

Answer:

$\large \boxed{\text{c = 2.50 mol/L; b = 3.96 mol/kg }}$

Explanation:

1. Molar concentration

Designate chloroform as C and acetone as A.

The molar concentration for C is derived from Moles of C per Litres of solution.

(a) Moles of C

We are assuming there are 0.187 moles of C.

This resolves that step.

(b) Litres of solution

Next, identify 0.813 moles of A.

(i) Mass of each component

$\text{Mass of C} = \text{0.187 mol C} \times \dfrac{\text{119.38 g C}}{\text{1 mol C}} = \text{22.32 g C}\\\\\text{Mass of A} = \text{0.813 mol A} \times \dfrac{\text{58.08 g A}}{\text{1 mol A}} = \text{47.22 g A}$

(ii) Volume of each component

$\text{Vol. of C} = \text{22.32 g C} \times \dfrac{\text{1 mL C}}{\text{1.48 g C}} = \text{15.08 mL C}\\\\\text{Vol. of A} = \text{47.22 g A} \times \dfrac{\text{1 mL A}}{\text{0.791 g A}} = \text{59.70 mL A}$

(iii) Volume of solution

Assuming mixing doesn't alter the total volume.

V = 15.08 mL + 59.70 mL = 74.78 mL

(c) Molar concentration of C

$c = \dfrac{\text{0.187 mol}}{\text{0.07478 L}} = \textbf{2.50 mol/L }\\\\\text{ The molar concentration of chloroform is $\large \boxed{\textbf{2.50 mol/L}}$}$

2. Molal concentration of C

Molal concentration is calculated as moles of solute per kilograms of solvent.

Total moles of C = 0.187 mol.

Mass of A = 47.22 g = 0.047 22 kg.

$\text{b} = \dfrac{\text{0.187 mol}}{\text{0.047 22 kg}} = \textbf{3.96 mol/kg }\\\\\text{The molal concentration of chloroform is $\large \boxed{\textbf{3.96 mol/kg}}$}$

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1 month ago

An -ateor -iteat the end of a compound name usually indicates that the compound contains _____.

Tems11 [2624]

A compound signifies a substance comprised of two or more elements that have undergone a chemical combination. A polyatomic ion, often referred to as a molecular ion, represents a charged particle formed from two or more atoms. An example would be the nitrate ion (NO3-), which consists of one nitrogen atom and three oxygen atoms covalently bonded, acting as a single charged entity. Thus, the apt term would be a polyatomic ion or a molecular ion.

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25 days ago

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