The amount to administer to the child is 2,469 mL.
To convert to kilograms (kg), the child's weight in pounds (lb) is multiplied by 0.45359237: m(child) = 72.6 · 0.045359237 = 32.93 kg.
To find m(Medrol), the child's mass in kilograms is multiplied by 1.5 mg/kg.
Thus, m(Medrol) = 32.93 kg · 1.5 mg/kg = 49.39 mg.
The concentration of Medrol is d(Medrol) = 20.0 mg/mL.
To find the volume of Medrol needed, use V(Medrol) = m(Medrol) ÷ d(Medrol).
So, V(Medrol) = 49.39 mg ÷ 20 mg/mL = 2,469 mL.
To determine the least degree of precision, we must base it on the mass of 4.05 kg or two decimal places. Thus, we add 0.56795 kg (0.57 kg) and 0.1001 kg (0.1 kg), resulting in a total of 4.72 kg.
<span>Conversely, to find the greatest degree of precision, we convert 4.05 kg into grams, which gives us 4050 g. Therefore, summing 4050 g with 567.95 g and 100.1 g yields 4718.05 grams, which rounds to 4718 g.</span>
<span>To determine the balanced chemical equation, it is necessary to identify the symbols and charges for each element and then balance the equation. This results in:
Al(OH)3(aq) + 3HBr(aq) ---> AlBr3(aq) + 3H2O(l)
The net ionic equation involves summing the charges and breaking them down into fundamental parts.
Al3+ + 3OH- + 3H+ + 3Br- --> Al3+ + 3Br + H3O+
After eliminating aluminum and bromine, we have:
3OH-(aq) + 3H+(aq) --> 3H2O(l)</span>
Answer:
THE MOLAR MASS OF XCL2 IS 400 g/mol
THE MOLAR MASS OF YCL2 IS 250 g/mol.
Explanation:
We derive the molar mass of XCl2 and YCl2 by recalling the molar mass formula when both mass and the number of moles are known.
Number of moles = mass / molar mass
Molar mass = mass / number of moles.
For XCl2,
mass = 100 g
number of moles = 0.25 mol
Thus, molar mass = mass / number of moles
Molar mass = 100 g / 0.25 mol
Molar mass = 400 g/mol.
For YCl2,
mass = 125 g
number of moles = 0.50 mol
Molar mass = 125 g / 0.50 mol
Molar mass = 250 g/mol.
Accordingly, the molar masses for XCl2 and YCl2 are 400 g/mol and 250 g/mol, respectively.
