Answer:
Theoretical yield = 31.8 g
Explanation:
The following formula is utilized to determine moles:

For 
Mass of
= 60.0 g
Molar mass of
= 101.96128 g/mol
The mole calculation formula is once again provided here:

Consequently,


Based on the provided reaction:
1 mole of aluminium oxide reacts with 3 moles of carbon
0.5885 mole of aluminium oxide reacts with
moles of carbon
Moles of carbon = 1.7655 moles
Available moles of carbon = 2.4978 moles
The limiting reagent is defined as the substance present in the smallest quantity. Hence, aluminium oxide serves as the limiting reagent.
The yield of the product is dictated by the limiting reagent. Thus,
1 mole of aluminium oxide results in the formation of 2 moles of aluminium.
0.5885 mole of aluminium oxide results in the formation of
moles of aluminium.
Moles of aluminium = 1.177 moles
Molar mass of aluminium = 26.981539 g/mol
Mass of aluminium = Moles × Molar mass = 1.177 × 26.981539 g = 31.8 g
Theoretical yield = 31.8 g