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3 days ago

How much water would form if 4.8 grams of hydrogen reacted with 38.4 grams of oxygen?

1 answer:

3 0

Hydrogen combines with oxygen to create water as shown in this equation:
2H2 + O2..............> 2H2O
This indicates that 4 grams of hydrogen is needed to react with 32 grams of oxygen to yield 36 grams of water.
We need to determine the amount of oxygen necessary to react with 4.8 grams of hydrogen. We can calculate this using cross multiplication as follows:
amount of oxygen = (4.8x32) / 4 = 38.4 grams

This suggests that there is no limiting reagent, and both reactants will fully react.
As we know, 4 grams of hydrogen generates 36 grams of water. Thus:
amount of water produced from 4.8 grams of hydrogen = (4.8 x 36) /4 = 43.2 grams

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A piece of lead loses 78.0 J ofheat and experiences a decrease in temperature of 9.0C the specific heat of lead is .130J/gC what

KiRa [2857]

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7 days ago

The standard cell potential (E°cell) for the reaction below is +0.63 V. The cell potential for this reaction is ________ V when

castortr0y [2913]

Answer: The cell potential for the given reaction stands at 0.50 V

Explanation:

The provided cell reaction is:

$Pb^{2+}(aq)+Zn(s)\rightarrow Zn^{2+}(aq)+Pb(s)$

The half-reactions are:

Anode oxidation half reaction: $Zn\rightarrow Zn^{2+}+2e^-$

Cathode reduction half reaction: $Pb^{2+}+2e^-\rightarrow Pb$

Initially, we need to find the cell potential for this reaction.

Utilizing the Nernst equation:

$E_{cell}=E^o_{cell}-\frac{2.303RT}{nF}\log \frac{[Zn^{2+}]}{[Pb^{2+}]}$

where,

F = Faraday's constant = 96500 C

R = gas constant = 8.314 J/mol·K

T = room temperature = $25^oC=273+25=298K$

n = electrons exchanged in oxidation-reduction = 2

$E^o_{cell}$ = standard electrode potential for the cell = +0.63 V

$E_{cell}$ = cell potential for the reaction =?

$[Zn^{2+}]$ = concentration of Zn²⁺ = 3.5 M

$[Pb^{2+}]$ = $2.0\times 10^{-4}M$

Now substituting all known values into the equation, we arrive at:

$E_{cell}=(+0.63)-\frac{2.303\times (8.314)\times (298)}{2\times 96500}\log \frac{3.5}{2.0\times 10^{-4}}$

$E_{cell}=0.50V$

So, the resulting cell potential for this reaction is 0.50 V

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6 days ago

You have a racemic mixture of d-2-butanol and l-2-butanol. the d isomer rotates polarized light by +13.5∘. what is the rotation

Anarel [2728]

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Thus, the rotation of the racemic mixture will be equal to 0°.

- This occurs because a racemic mixture contains equal proportions of both enantiomers.

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1 month ago

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lions [2782]

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VMariaS [2860]

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