Phyllis had always been the one to take care of Douglas, now he feels as if it is his duty and privilege to take care of her, ev

Answer: The result to the query is 0.25 ohms

Explanation:

R = u x/A.......1

where u represents the resistivity of the

rod, A is the cross-sectional area, and x denotes

the length of the rod.

Let R* represent the resistance across the adjacent sections of the rod.

Then, R* = u1/4.......2

By comparing equation 1 with equation 2, we find that

R* = 1/4

which equals 0.25 ohms.

Answer:

The value of Y is -10°.

Explanation:

For scale X, the freezing point is 40° and the boiling point is 120°.

The gap between the two endpoints for scale X = 120 - 40 = 80

For scale Y, the ice point and steam point are -30° and 130° correspondingly.

The difference between these two points for scale Y = 130 - (-30) = 160

Comparing both scales:

One unit in scale X is x

One unit in scale Y is y

Scale X consists of 80 divisions, while scale Y has 160

80x = 160y

x = 2y

50° on scale X equals 10x plus the freezing point of scale X

10 divisions in scale Y correspond to 20y

The reading on scale Y = the ice point of Y + 20y

= -30° + 20°

= -10°

Answer:

a) W =400 kJ

b) W = 0 kJ

c) W =-160.944 KJ

Explanation:

Given

Process 1 ---> 2

Pressure at point (1) P1 = 10 bar = P2

Volume at point (1) V1 = 1 m^3

Volume at point (2) V2 =4 m^3

For Process 2 ---> 3, where V = constant

Pressure at point (3) P3 = 10 bar

Volume at point (3) V3 = 4 m^3

Process 3 ---> 1 defined as PV = constant.

Required

Sketch the processes on the PV coordinates To calculate the work in kJ

Work is calculated by W=

a=V2

b=V1

x=Pdx=dV

W=

a=V3

x=4dx=dV

W=400 kJFor Process 2 ---> 3

As V = constant in this case, the volume remains unchanged, resulting in W = 0 kJ  

For Process 3 ---> 1  By applying point (1) --> 5 x.2 = C ---> C = 1 P = 5V^-1  

a=V1

x=1V^-1dx=dVsubstituting values into this integral results in

  = -160.944 KJ

Answer:

He requires more because his level of physical activity is higher, implying he exerts his body more and needs additional energy compared to someone who is sedentary in an office. The computer operator would not require as much energy as the bricklayer.