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Volgvan
3 months ago
13

A person is rowing across the river with a velocity of 4.5 km/hr northward. The river is flowing eastward at 3.5 km/hr (Figure 4

). What is the magnitude of her velocity ( v ) with respect to the shore?

Physics
1 answer:
Yuliya22 [3.3K]3 months ago
8 0

Answer: Her velocity magnitude (v) relative to the shore is 5.70 km/h.

Explanation:

Let Q be the speed of the boat, and P be the speed of the river flow.

R represents the resultant velocity combining boat velocity and river current.

According to vector addition using the law of triangles:

R=\sqrt{P^2+Q^2+2PQCos\theta}

From the diagram:

P = 3.5 km/h, Q = 4.5 km/h

\theta= 90^o

R=\sqrt{P^2+Q^2+2PQCos\theta}=\sqrt{(3.5)^2+(4.5)^2+3.5\times 4.5\times cos90^o}=5.70

(Cos90^o=0),(sin 90^o=1)

\alpha =tan^{-1}\frac{Qsin\theta}{P+Qcos\theta}=tan^{-1}\frac{4.5 sin 90^o}{3.5+4.5 cos90^o}=tan^{-1}\frac{4.5}{3.5}=52.12^o

Therefore, her velocity magnitude relative to the shore is 5.70 km/h.

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Answer:

b. The loop's current consistently flows in a counterclockwise direction.

Explanation:

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3 months ago
On a hypothetical scale X The ice point is 40° and steam point is 120°.
ValentinkaMS [3465]

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The value of Y is -10°.

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For scale X, the freezing point is 40° and the boiling point is 120°.

The gap between the two endpoints for scale X = 120 - 40 = 80

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The difference between these two points for scale Y = 130 - (-30) = 160

Comparing both scales:

One unit in scale X is x

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2 months ago
Resistance of rod is 1 ohm. It is bent in the form of square. The resistance across adjoint corners is.​
Keith_Richards [3271]

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Explanation:

R = u x/A.......1

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3 months ago
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