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3 hours ago

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A student claims that earthquakes are more destructive than tsunamis. In one or two sentences, explain at least two reasons that

support the student’s claim.
if you do not know the answer DO NOT ANSWEAR IT PLEASE

1 answer:

ValentinkaMS [2.4K]2 hours ago

8 0

An earthquake can impact individuals on land, causing greater destruction than a tsunami, which primarily affects those near the ocean.

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Calculate the mass (in kg) of 54.3 m³ of granite. The density of granite is 2700 kg/m³. Give your answer to 2 decimal places.

Ostrovityanka [2214]

Answer:

Explanation:

Density is defined as d=m/v.

To find mass, the formula transforms into:

m=d*v

m=2700*54.3

m=146610

m=14.6*10^4

6 0

14 days ago

A block with mass m1 = 4.50 kg and a ball with mass m2 = 7.70 kg are connected by a light string that passes over a frictionless

inna [2223]

A block weighing m1 = 4.50 kg and a ball weighing m2 = 7.70 kg are linked by a light string over a frictionless pulley, as illustrated in figure (a). The coefficient of kinetic friction between the block and the surface is 0.300.
(a) Determine the acceleration of both objects and the tension present in the string.
(b) Verify the acceleration calculation using a systems approach. (Utilize m1, m2, μk, and g as needed.)
(c) If an additional mass is added to the ball, what amount is necessary to augment the downward acceleration by 60%?

In (a), I calculated the acceleration to be 5.10 m/s^2 and the tension to be 36.2N.
In (b), the equation used is a = (m2g-ukm1g)/(m1+m2)
It’s (c) that I am struggling to understand. Can anyone assist me?

4 0

9 days ago

A stationary 1.67-kg object is struck by a stick. The object experiences a horizontal force given by F = at - bt2, where t is th

serg [2598]

Answer:

$v_{f}$ = 3289.8 m/s

Explanation:

This problem can be approached using momentum definitions.

I = ∫ F dt

We substitute and compute.

I = ∫ (at - bt²) dt

Integrating gives us:

I = a t² / 2 - b t³ / 3

We will evaluate between the limits I=0 for t = 0 ms and higher I=I for t = 2.74 ms:

I = a (2.74² / 2- 0) - b (2.74³ / 3 -0)

I = a 3.754 - b 6.857

Substituting the values for a and b, we find:

I = 1500 3.754 - 20 6.857

I = 5,631 - 137.14

I = 5493.9 N s

Next, we engage the relationship between impulse and momentum:

I = Δp = m $v_{f}$ - m v₀o

I = m $v_{f}$ - 0

$v_{f}$ = I / m

$v_{f}$ = 5493.9 /1.67

$v_{f}$ = 3289.8 m/s

5 0

1 month ago

Raphael refers to a wave by noting its wavelength. lucinda refers to a wave by noting its frequency. which student is correct an

Keith_Richards [2268]

Both students are correct because they highlight different aspects of waves. Raphael describes the wave in terms of its wavelength, while Lucinda focuses on its frequency, showing that both measurements are valid.

7 0

20 days ago

A particle has a charge of -4.25 nC.

kicyunya [2264]

Answer:

-611.32 N/C

0.43723 m

Explanation:

k = Coulomb constant = $8.99\times 10^{9}\ Nm^2/C^2$

q = Charge = -4.25 nC

r = Distance from particle = 0.25 m

The electric field can be calculated using

$E=\dfrac{kq}{r^2}\\\Rightarrow E=\dfrac{8.99\times 10^9\times -4.25\times 10^{-9}}{0.25^2}\\\Rightarrow E=-611.32\ N/C$

The calculated magnitude is 611.32 N/C

The electric field direction is vertically downward due to the negative charge.

$E=\dfrac{kq}{r^2}\\\Rightarrow r=\sqrt{\dfrac{kq}{E}}\\\Rightarrow r=\sqrt{\dfrac{8.99\times 10^9\times 4.25\times 10^{-9}}{13}}\\\Rightarrow r=1.71436\ m$

The distance from the electric field source is 1.71436 m

4 0

1 month ago

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