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10 days ago

Suggest one reason why the bricklayer needs a higher energy diet than the computer operator

Physics

1 answer:

Sav [3.1K]10 days ago

7 0

Answer:

He requires more because his level of physical activity is higher, implying he exerts his body more and needs additional energy compared to someone who is sedentary in an office. The computer operator would not require as much energy as the bricklayer.

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A cleaver physics professor wants to create a situation where a block starts from rest at the top of a 31.0° inclined plane and

Softa [3030]

Let L be the length of the inclined plane. The work done by gravity on the block is calculated as the product of force and distance traveled, which amounts to mg sinθ x L, where m stands for the mass of the block and θ denotes the angle of inclination. This translates into the potential energy of the compressed spring represented by 1/2 k x² = mgL sin31, with k as the spring constant. Compression x measures 0.37. Solving this gives: 0.5 x 3400 x 0.37² = 33 x 9.8 x sin31 L yields L = 1.4 m, indicating the incline measures 1.4 meters.

8 0

11 days ago

Calculate the partial pressure of ozone at 441 ppb if the atmospheric pressure is 0.67 atm.

kicyunya [3294]

Answer:

$2.95\times 10^{-7}atm$

Explanation:

It's provided that

Atmospheric pressure=0.67 atm

We need to determine the partial pressure of ozone at 441 ppb.

Partial pressure of ozone= $\frac{441\times atmospheric\;pressure}{10^9} atm$

Inserting the given atmospheric pressure

Thus, we find

Partial pressure of ozone= $\frac{441\times 0.67}{10^9}=2.95\times 10^{-7} atm$

Consequently, the partial pressure of ozone is= $2.95\times 10^{-7}atm$

5 0

15 days ago

At time t=0 a proton is a distance of 0.360 m from a very large insulating sheet of charge and is moving parallel to the sheet w

serg [3582]

Explanation:

The formula for the electric field produced by an infinite sheet of charge is outlined below.

E = $\frac{\sigma}{2 \epsilon_{o}}$

where, $\sigma$ is the surface charge density

Following this, the formula for the electric force acting on a proton is given as:

F = eE

where, e is the charge of a proton

According to Newton's second law of motion, the overall force on the proton can be expressed as follows.

F = ma

a = $\frac{eE}{m}$

= $\frac{e(\frac{\sigma}{2 \epsilon_{o}})}{m}$

= $\frac{e \sigma}{2m \epsilon_{o}}$

According to kinematic equations, the proton's speed in the perpendicular direction can be described as follows.

$v_{f} = v_{i} + at$

= $(0 m/s) + \frac{e \sigma}{2 m \epsilon_{o}}t$

= $\frac{1.6 \times 10^{-19}C \times 2.34 \times 10^{-9} C/m^{2} \times 5.40 \times 10^{-8}s}{2 \times (1.67 \times 10^{-27} kg)(8.85 \times 10^{-12} C^{2}/Nm^{2}}$

= 683.974 m/s

Thus, the overall speed of the proton can be calculated as follows.

v' = $\sqrt{(960 m/s)^{2} + (683.974 m/s)^{2}}$

= $\sqrt{921600 + 467820.43}$

= $\sqrt{1389420.43}$

= 1178.73 m/s

Consequently, we conclude that the proton's speed is 1178.73 m/s.

3 0

20 days ago

In a third class lever, the distance from the effort to the fulcrum is ____________ the distance from the load/resistance to the

serg [3582]

The full sentence states:
In a third class lever, the distance between the effort and the fulcrum is LESS than the distance between the load/resistance and the fulcrum.
In a third class lever, the fulcrum is positioned on one end of the effort, while the load/resistance is on the opposite side, placing the effort somewhere in between. Consequently, the distance from the effort to the fulcrum is less than that from the load to the fulcrum.

4 0

29 days ago

A student is trying to classify an unidentified, solid gray material as a metal or a nonmetal. Which question will best help the

kicyunya [3294]

The most effective question for the student to determine whether the substance is metal or nonmetal would be option C.

8 0

18 days ago

Read 2 more answers