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gladu
12 days ago
6

Which graph shows the solution to the system of linear inequalities? x – 4y < 4 y < x + 1 Image for option 1 Image for opt

ion 2 Image for option 3 Image for option 4

Mathematics
1 answer:
Inessa [3.9K]12 days ago
7 0

Answer:

The graph provided in the accompanying figure

Step-by-step explanation:

we have

x-4y ----> inequality A

solving for y

-4y

4y>x-4

y> (x/4)-1

The shaded area above the dashed line denotes the solution for inequality A

The slope of the dashed line is positive

The y-intercept corresponds to the point (0,-1)

The x-intercept corresponds to the point (4,0)

y< x+1 ----> inequality B

The solution for inequality B is represented by the shaded area below the dashed line

The slope of the dashed line is positive

The y-intercept corresponds to the point (0,1)

The x-intercept corresponds to the point (-1,0)

Using a graphing tool

This illustrates the solution for the system of inequalities in the provided figure

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A solid oblique cone with a slant length of 17 units is placed inside an empty cylinder with a congruent base of radius 8 units
PIT_PIT [3919]

Step 1

Calculate the volume of a cylinder

We understand that

the volume of a cylinder can be expressed as

V1=\pi r^{2} h

In this scenario

r=8\ units \\ h=15\ units

Insert the values

V1=\pi 8^{2} 15

V1=960\pi\ units^{3}

Step 2

Calculate the volume of a cone

We are aware that

the volume of a cone equals

V2=\frac{1}{3}\pi r^{2} h

In this example

r=8\ units \\ l=17\ units \\ h=?

Use the Pythagorean Theorem to determine the height h

h^{2} =l^{2}-r^{2}\\ h^{2} =17^{2}-8^{2}\\ h^{2}=225\\ h=15\ units

V2=\frac{1}{3}\pi 8^{2} 15\\ \\ V2=320\pi \ units^{3}

Step 3

Calculate the empty volume inside the cylinder

V1-V2=960\pi -320\pi =640\pi \ units^{3}

Thus

the final result is

the empty volume inside the cylinder is 640\pi \ units^{3}

6 0
8 days ago
Read 2 more answers
What is the value of n? 9x27+2x31-28= n
Svet_ta [4321]

n equals 277

9 multiplied by 27 plus 2 multiplied by 31 minus 28 gives n

243 plus 62 minus 28 results in n

305 minus 28 equals n

which means 277 is n


3 0
11 days ago
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A recipe calls for 400 grams of flour. if leena makes one quarter of the recipe, how many kilograms of flour will she need?
Svet_ta [4321]
Additional 300 grams of flour will be required.
4 0
4 days ago
Part A: Rhett made $250 washing cars with his mobile car wash company. He charges $70 per car and earned $50 in tips. Write an e
babunello [3635]

Conclusion:

Please refer to the explanation provided.

Detailed explanation:

Starting with these facts:

Total revenue = $250

Fee charged = $70 per car

Tips received = $50

Equation 1 representing the above:

(Fee per car × number of cars) + tips = total revenue

Let the number of cars be c.

Thus, we have:

$70c + $50 = $250

Part B:

Total revenue = $250

Fee charged = $75 per car

Tips received = $35

Supplies cost per car washed = $5

Equation 2:

(Fee per car × number of cars) + tips - (supplies cost × number of cars) = total revenue

$75c + $35 - $5c = $250

$70c + $35 = $250

Part C:

Equation 1 does not factor in costs associated with washing the car, while equation 2 does incorporate costs, which are deducted from the amount charged per car. Additionally, tips in equation 1 total $50 compared to a $35 fee in equation 2.

3 0
16 days ago
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Initially 5 grams of salt are dissolved into 10 liters of water. Brine with concentration of salt 5 grams per liter is added at
Svet_ta [4321]

The salt enters at a rate of (5 g/L)*(3 L/min) = 15 g/min.

The salt exits at a rate of (x/10 g/L)*(3 L/min) = 3x/10 g/min.

Thus, the total rate of salt flow, represented by x(t) in grams, is defined by the differential equation,

x'(t)=15-\dfrac{3x(t)}{10}

which is linear. Shift the x term to the right side, then multiply both sides by e^{3t/10}:

e^{3t/10}x'+\dfrac{3e^{t/10}}{10}x=15e^{3t/10}

\implies\left(e^{3t/10}x\right)'=15e^{3t/10}

Next, integrate both sides and solve for x:

e^{3t/10}x=50e^{3t/10}+C

\implies x(t)=50+Ce^{-3t/10}

Initially, the tank contains 5 g of salt at time t=0, so we have

5=50+C\implies C=-45

\implies\boxed{x(t)=50-45e^{-3t/10}}

The duration required for the tank to contain 20 g of salt is t, such that

20=50-45e^{-3t/10}\implies t=\dfrac{20}3\ln\dfrac32\approx2.7031\,\mathrm{min}

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