Answer:
CrO₃.
Step-by-step explanation:
First, we will find the chromium percentage in the oxide by using the following process:
Oxygen (O) = 48%
Chromium (Cr) =?
The oxide consists solely of chromium and oxygen, and its chromium percentage is calculated as:
Cr = 100 – percentage of oxygen
Cr = 100 – 48
Cr = 52%
Next, we will determine the empirical formula for the oxide:
Chromium (Cr) = 52%
Oxygen (O) = 48%
Now, we divide by their molar mass:
Cr = 52/52 = 1
O = 48/16 = 3
Now, divide by the lowest value:
Cr = 1/1 = 1
O = 3/1 = 3
Thus, the empirical formula for the oxide is CrO₃.
Answer:
Given that the frog jumps every 10 seconds
(using digits from a random number table)
- It requires 7 jumps with 2 in the reverse direction (either left or right) for the frog to get off the board in 60 seconds.
- Alternatively, 3 jumps in the same direction will also lead to the frog being off the board.
- Furthermore, it would take 5 jumps with one in the opposite direction within the time limit of 60 seconds to leave the board.
Step-by-step explanation:
A frog positioned right at the center of a 5ft long board is 2.5 ft away from either edge.
Every 10 seconds, the frog jumps left or right.
If the frog's jumps are LLRLRL, it will remain on the board at the leftmost square.
If it jumps as LLRLL, it will jump off the board after fifty seconds.
Given that the frog jumps every 10 seconds
(using digits from a random number table)
- It requires 7 jumps with 2 in reverse direction (either left or right) for the frog to get off the board in 60 seconds.
- Alternatively, 3 jumps in the same direction will also lead to the frog being off the board.
- Furthermore, it would take 5 jumps with one in the opposite direction within the time limit of 60 seconds to leave the board.
Greetings:
<span>(4y-3)²=72
4y-3 = </span>±√72
thus, y= (3+√72) /4 or y= (3 - √72) /4
