A closed system of mass 10 kg undergoes a process during which there is energy transfer by work from the system of 0.147 kJ per

The elevator's acceleration is 0.422 m/s². To clarify the solution: By applying Newton's Law, the net forces in the motion's direction equal the mass multiplied by the acceleration. The forces comprise 460 N in the motion's direction and the person's weight acting in the opposite direction... The weight is determined by the mass and gravity's acceleration (W = mg). Here m = 45 kg and g = 9.8 m/s², leading to W = 441 N. With the scale indicating 460 N, we apply F - W = ma, yielding 19 = 45 a. Dividing both sides by 45 gives a = 0.422 m/s².

The force exerted by the car on the bug is identical to the force the bug applies back on the car.

Answer:

Distance: 4.6 km Displacement= -0.2 km

Explanation:

The overall distance covered: 1.5 + 2.4 + 0.7 = 4.6 km

Displacement calculation: 1.5 - 2.4 + 0.7 = -0.2 km

The displacement could also simply be stated as 0.2 km depending on whether negative value is preferred.

The half-life for substance A is determined to be 17.1 days. To explain: The half-life for substance B is noted to be 1.73 days. Let’s convert the 3 days elapsed time into terms of half-lives of B: 1.37 days equates to 1 half-life of B, implying 3 days translates to multiples of half-lives of B, specifically 2.19 half-lives. Consequently, the quantity of A in regard to B is expressed as follows: A = 4.04 B. For B, we can express the quantity after n half-lives as B0 / 2ⁿ. Hence, applying these relationships after 2.19 half-lives results in adjusting A similarly as A0 / 2ⁿ. Our derived equations lead us to relate the two expressions through substitutions where after cancelling A0, we derive the final calculation: 2ⁿ = 4.04 divided by 2^(2.19), which ultimately simplifies leading to 1 half-life of A totaling 17.1 days.

Answer:

Cl2 concentration: 1,048 ppm

Explanation:

Molarity (M) is a unit that indicates how many moles of a substance are in one liter of solution, while ppm is similar to mg/L, representing the mass of the substance per liter. To convert M to ppm, we need to consider both mass and volume. The volume remains in liters in both cases, so no adjustments are needed there. The challenge arises when converting moles from molarity to milligrams for the mg/L conversion to find ppm.

First, we must recognize that the substance in question is Cl2, prompting the need to connect mole quantity to its mass. Referring to the periodic table, we find the atomic weight of Cl is 35.4 g/mole. This relationship allows us to establish moles' mass, as shown in the following equation:

We already know the moles of Cl2 in the solution is (moles=2.96x10^-5). Substituting this value, we can calculate:

Keep in mind that we're discussing the mass found per liter of solution, which gives us 1.048x10^-3 g/L. We previously established that ppm equals mg/L, so we need to convert grams to milligrams:

1 g = 1000 mg

Now multiplying both sides by 1.048x10^-3:

1 * 1.048x10^-3 g = 1000 * 1.048x10^-3 mg

Thus, 1,048x10^-3 g translates to 1,048 mg.

This amount of mass detected in one liter indicates that the concentration of the substance in the solution is:

1,048 mg/L

Since we know that mg/L=ppm, the conclusion is:

1,048 ppm