Answer:
Please include the diagrams and repost them.
Answer:
14523.55J
Explanation:
The work exerted by the jogger against gravitational forces is represented by the following equation:

where m signifies mass, g represents gravitational acceleration taken as
, and h denotes the elevation of the hill.
Given that the hill measures 132m in length and is inclined at an angle of 12 degrees to the horizontal, the height can be calculated as follows;

Substitute this value into equation (1) along with all other required parameters to arrive at the result;

To address this issue, we apply the de Broglie equation written as:
λ = h/mv
where h equals 6.626×10⁻³⁴ J·s
Solving for m, we substitute for v, which is 46.9 m/s:
9.74 × 10⁻³⁵ m = 6.626×10⁻³⁴ J·s / (m)(46.9 m/s)
Thus, we find that m = 0.145kg
a) The work done at constant pressure can be calculated as P x Δ V which equals 200 x 10³ x (.1 -.04) = 12 x 10³ J. b) For isothermal work done, the formula is n RT ln(v₂ / v₁) = PV ln(v₂ / v₁), resulting in 200 x 10³ x.04 ln(1/.04) = 8 x 10³ x.916 = 7.33 x 10³ J.