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meriva
2 days ago
15

A 3030 cmcm wrench is used to loosen a bolt with a force applied 0.30.3 mm from the bolt. It takes 6060 NN to loosen the bolt wh

en the force is applied perpendicular to the wrench. How much force would it take if the force was applied at a 3030 degree angle from perpendicular?A 3030 cmcm wrench is used to loosen a bolt with a force applied 0.30.3 mm from the bolt. It takes 6060 NN to loosen the bolt when the force is applied perpendicular to the wrench. How much force would it take if the force was applied at a 3030 degree angle from perpendicular?
Physics
1 answer:
Softa [2.6K]2 days ago
7 0

Complete Question

A 30 cm cm wrench is employed to loosen a bolt, with force applied 0.30m from the bolt. It requires 60 N to loosen the bolt when force is applied perpendicular to the wrench. How much force would be necessary if the force were applied at a 30-degree angle from perpendicular?

Response:

The strength needed is F_{\theta } = 69.28 \ N

Clarification:

According to the problem, we know that

    The length of the wrench is L = 30 cm = \frac{30}{100} = 0.3 \ m

    The distance from the bolt is  d = 0.30 m

      The force necessary to loosen the bolt is F = 60 N

       The angle of application is \theta = 30 ^o

Generally, the torque required for loosening the bolt is defined as

       \tau = F * d

        \tau = 60 * 0.3

        \tau = 18 Nm

Now for the bolt to loosen at \theta the torque at 90° must equal that at \theta

Thus, the torque at \theta is represented mathematically as

          \tau = F_{\theta }d cos \theta

substituting values gives us

           18 = F_{\theta } * 0.3 cos (30)

           F_{\theta } = \frac{18}{0.3 cos (30)}

           F_{\theta } = 69.28 \ N

       

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