Answer:
La conclusión sobre p utilizando una desigualdad de valor absoluto es
Explicación paso a paso:
Según el enunciado, nos informan que
La proporción de la muestra es 
El margen de error es 
El intervalo de confianza se representa matemáticamente como
=> 
=>
The average years of employment is 14
with 73% having worked for at least 10 years.
To find the mean, add up the years of service and divide by the number of employees. The total years worked is 417, so the formula yields:
average years worked = 417/30 = 13.9, rounded to approximately 14 years.
To determine the percentage of employees with ten or more years, count those with 10 or more years and divide by the total employee count, converting the result into a percentage:
(10 years or over)/(total number) = 22/30 = 0.73 repeating, which approximates to 73%.
Using a spreadsheet tool can make this calculation simpler, as it can quickly compute the average and help tally how many employees have worked for 10 years or more.
Answer:
Step-by-step breakdown:
You may consider a structure like the following while keeping in mind your specific notation.
1. | ~( (~Q ->~R) v (R & ~Q) ) Assume
2. | | ~(~Q ->~R) Assume
3. | | | ~(R & ~Q) Assume
4. | | | ~R v Q 3, De Morgan
5. | | | ~Q -> ~R 4 Material implication
6. | | | # 2, 5 Results in a contradiction
7. | | R & ~Q 3-6 indirect proof outcome
8. | ~(~Q ->~R) -> (R & ~Q ) 2-7 Discharging the conditional proof
9. | (~Q ->~R) v (R & ~Q) 8 Material implication derived
10 | # 1,9 Results in contradiction
11. (~Q ->~R) v (R & ~Q) 1-10 Completion via indirect proof
Response:
m(n) = 60000
Amount = 60000/n
Step-by-step breakdown:
Provided
Budget = 60000
Solving part (a) as a function mn
To achieve this, simply substitute m(n) for the budget amount.
This results in;
m(n) = 60000
Solving part (b) for the amount each committee is allocated.
Given that the budget will be evenly split.
Amount = m(n)/n
Replace m(n) with 60000
Amount = 60000/n
