A compact car has a maximum acceleration of 4.0 m/s2 when it carries only the driver and has a total mass of 1200 kg . you may w

C. The rate of water flow diminishes.

Position or composition

Answer:

Explanation:

The data indicates that point A is located midway between two charges.

To calculate the electric field at point A, we begin with the field produced by charge -Q ( 6e⁻ ) at A:

= 9 x 10⁹ x 6 x 1.6 x 10⁻¹⁹ / (2.5)² x 10⁻⁴

= 13.82 x 10⁻⁶ N/C

This field points towards Q⁻.

A similar field will arise from the charge Q⁺, but it will direct away from Q⁺ toward Q⁻.

To find the resultant field, we add these contributions:

= 2 x 13.82 x 10⁻⁶

= 27.64 x 10⁻⁶ N/C

For the force acting on an electron placed at A:

= charge x field

= 1.6 x 10⁻¹⁹ x 27.64 x 10⁻⁶

= 44.22 x 10⁻²⁵ N

The work done can be calculated using the equation:

Work = Force x Distance = Change in kinetic energy

The kinetic energy is derived using the following formula: KE = (1/2)*m*v^2
Thus, the change in kinetic energy is calculated as (1/2)*m*(Vf)^2 - (1/2)*m*(Vo)^2

Where:

Vf represents the final speed = 90 kph = 25 m/s
Vo denotes the initial speed = 72 kph = 20 m/s

By substituting in the given values:

Work = (1/2)*2500*(25^2) - (1/2)*2500*(20^2) = 281250 J, which can also be represented as 2.8 x 10^5 Joules.

The correct choice among the options is A.

Answer:

The total energy saving achieved will be 0.8 KWH

Explanation:

It is provided that there are 50 long light bulbs rated at 100 W, thus the total power consumed by 50 bulbs equals 100×50 = 5000 W = 5 KW

Additionally, 30 bulbs are rated at 60 W

Consequently, the total power consumption of 30 bulbs is 30×60 = 1800 W = 1.8 KW

The cumulative power of all 80 bulbs is 1.8 + 5 = 6.8 KW

Considering the operation time of 3 hours

We know that energy

Now, the power consumption per CFL bulb equals 25 W

Thus for 80 bulbs, power equals 80×25 = 2000 W = 2 KW

So the energy for 80 bulbs amounts to 2×3 = 6 KWH

Hence, the overall energy saving is 6.8 - 6 = 0.8 KWH