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vodomira
1 day ago
10

An ideally efficient heat pump delivers 1000 J of heat to room air at 300 K. If it extracted heat from 260 K outdoor air, how mu

ch of that delivered heat was originally work consumed in the transfer?
Physics
1 answer:
Yuliya22 [1.1K]1 day ago
5 0

Answer:

Wnet, in, = 133.33J

Explanation:

Provided that

Pump heat QH = 1000J

Hot temperature TH= 300K

Cold temperature TL= 260K

Given the heat pump is entirely reversible, the performance coefficient expression is formulated as follows:

According to the first law of thermodynamics,

COP(HP, rev) = 1/(1-TL/TH)

COP(HP, rev) = 1/(1-260/300)

COP(HP, rev) = 1/(1-0.867)

COP(HP, rev) = 1/0.133

COP(HP, rev) = 7.5

The power necessary to operate the heat pump is given by

Wnet, in = QH/COP(HP, rev)

Wnet, in = 1000/7.5

Wnet, in = 133.333J. QED

Thus, the 133.33J represents the initial work input during the heat transfer process.

<padditionally...><pbased on="" the="" first="" law="" rate="" at="" which="" heat="" is="" extracted="" from="" lower="" temperature="" reservoir="" calculated="" as="">

QL=QH-Wnet, in

QL=1000-133.333

QL=866.67J

</pbased></padditionally...>
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Estimate the monthly cost of using a 700-W refrigerator that runs for 10 h a day if the cost per kWh is $0.20.
ValentinkaMS [1149]

The refrigerator's power consumption is as follows:

P = 700 W

If the refrigerator operates for 10 hours daily, the total monthly usage will be calculated as:

t = 10 * 30 = 300 h

Consequently, the overall energy consumed in a month is expressed as:

E = P * t

E = 700 * 300

E = 210000

E = 210 kWh

It’s noted that the price of one kWh is $0.20, leading to the total cost for one month being:

C = $0.20 * 210

C = $42


7 0
2 days ago
Two loudspeakers 42.0 m apart and facing each other emit identical 115 Hz sinusoidal sound waves in a room where the sound speed
ValentinkaMS [1149]

Answer:

She will be located in a loud area.

Explanation:

To evaluate whether Susan is situated in a quiet or loud area, we must first ascertain the difference in the sound waves reaching her from the two speakers.

If we refer to d₁ as the distance to speaker A, which measures 19.5 m, then d₂ to the other speaker is calculated as follows:

d₂ = 42.0 m - 19.5 m = 22.5 m

This reveals that the path difference between both speakers is:

d = d₂-d₁ = 22.5 m -19.5 m = 3.0 m

Next, we relate this distance to the sound wave's wavelength; for constructive interference, the path difference must equal an even multiple of half the wavelength:

d = (2n)*(λ/2)

To determine λ, we know that for any wave, the relationship between speed, frequency, and wavelength holds:

v = λ*f

<pwhere v="345" m="" and="" f="115" we="" can="" calculate="">

λ = v/f = 345 m/s / 115 (1/s) = 3.0 m.

Since the difference between the distances to Susan from both speakers corresponds exactly to one wavelength, this indicates that both waves arrive at the same phase, resulting in constructive interference, thus labeling it as a loud area.

</pwhere>
5 0
3 days ago
A BMX bicycle rider takes off from a ramp at a point 2.4 m above the ground. The ramp is angled at 40 degrees from the horizonta
Ostrovityanka [942]

Answer:

The BMX rider lands 5.4 meters horizontally away from the ramp's end.

Explanation:

The BMX position vector is represented as:

r = (x0 + v0 × t × cos α, y0 + v0 × t × sin α + ½ × g × t²)

Where:

r = position at time t

x0 = initial horizontal position

v0 = initial speed

α = angle of jump

y0 = initial vertical height

g = gravitational acceleration (-9.8 m/s², upward positive)

Refer to the diagram for clarity. At the landing time, the vertical coordinate of the position vector is -2.4 m, measured from the ramp's edge as the origin. Using the vertical component equation for y, one can solve for t, then substitute t to find the horizontal distance.

The vertical position equation:

-2.4 m = 0 + 5.9 m/s × t × sin 40° - ½ × 9.8 m/s² × t²

Rearranged:

0 = -4.9 t² + 5.9 t × sin 40° + 2.4

Solving this quadratic yields:

t = 1.2 seconds

Then, calculate horizontal distance:

x = 0 + 5.9 m/s × 1.2 s × cos 40° = 5.4 m

This means the BMX lands 5.4 meters from the ramp's edge.

Have a great day!

8 0
14 days ago
Mrs. Gonzalez is about to give birth and Mr. Gonzalez is rushing her to the hospital at a speed of 30.0 m/s. Witnessing the spee
Ostrovityanka [942]

Answer: The frequency is 1714.3 Hz

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Since the source is approaching the observer, the observer's velocity is considered positive.

Refer to the attached document for the detailed derivation

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13 days ago
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Maru [1056]

Answer:

Explanation:

Each of the processes connected to these molecules varies.

For instance, water that has accumulated in the atmosphere returns to the ground as rain. Cows utilize this water from local water sources. This represents one method in which water transitions from the atmosphere to the cow's body.

Regarding carbon and nitrogen, the air inhaled by cows contains nitrogen, oxygen, carbon dioxide, and other gases. These molecules enter the cow through respiration.

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2 days ago
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