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Andreas93
3 months ago
15

You should have observed that there are some frequencies where the output is stronger than the input. Discuss how that is even p

ossible from a conservation of energy standpoint. Also, can you relate this behavior to the transient (natural) response of the circuit that you observed in the previous lab
Physics
1 answer:
Maru [3.3K]3 months ago
6 0

Answer:

w = √ 1 / CL

This scenario does not breach the principle of energy conservation since the power source's voltage matches the resistance's voltage drop.

Explanation:

This issue pertains to electrical circuits, specifically series RLC circuits, where the resistor, capacitor, and inductor are arranged in series.

In these types of circuits, impedance can be calculated as follows:

X = √ (R² +  (X_{C} -X_{L})² )

Where Xc and XL denote capacitive and inductive impedance, respectively.

X_{C} = 1 / wC

X_{L} = wL

The resonance frequency condition

X_{C} = X_{L}

results in minimal circuit impedance, which maximizes both current and voltage, leading to an observable increase in signal strength.

This phenomenon does not violate energy conservation, as the power source voltage equals the voltage drop across the resistance:

V = IR

Since the impacts of the other two components are neutralized, this occurs for

X_{C} = X_{L}

1 / wC = w L

w = √ 1 / CL

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Ostrovityanka [3204]

The result is -15.625 m/s².


Acceleration signifies the alteration of velocity over a specified duration. It can be calculated with this formula:


a = \dfrac{vf-vi}{t}

Where:

vf = final velocity

vi = initial velocity

t = time

Let’s examine the information provided in your query:

Initially, the vehicle was traveling at 25 m/s before coming to a halt. Thus, it was in motion and subsequently ceased moving, indicating that the final velocity is 0 m/s.


However, we notice that the problem does not provide a time value. We need to determine the time taken from when it was in motion to when it reached the traffic light located 20 m away.


The time can be calculated using the kinematics equation:

d = \dfrac{vi+vf}{2} *t


We derive the equation by substituting the known values first.

20m = \dfrac{25m/s+0m/s}{2}(t)

20m = 12.5m/s{2}(t)

\dfrac{20m}{12.5m/s}=t
1.6s=t

The duration from when it was in motion until it stopped is 1.6s. Now we can utilize this in our acceleration calculation.


a = \dfrac{0m/s-25m/s}{1.6s}

a = \dfrac{-25m/s}{1.6s}

a = -15.625m/s^{2}


It is important to note that the acceleration is negative, indicating the vehicle slowed down.

8 0
3 months ago
Read 2 more answers
Two charges q1 = 5 µC, q2 = -26 µC, are L = 19 cm apart. A third charge is to be placed on the line between the two charges. How
Keith_Richards [3271]
The electric force between two objects is expressed as being proportional to the product of their charges and inversely proportional to the square of the distance separating them. In this instance, the distance between the first two charges is 19 cm. We formulate the equation k q1 q3/ (x)^2 = k q2 q3/ (19-x)^2, where x denotes the separation between q1 and q3. The charge q3 cancels out, and q2 is used in absolute terms. The resulting value of x is 5.79 cm.
6 0
2 months ago
Three balls of equal mass are fired simultaneously with equal speeds from the same height h above the ground. Ball 1 is fired st
Ostrovityanka [3204]

Answer:

d) v1 = v2 = v3

Explanation:

This can be determined through the principle of energy conservation. We assess the total mechanical energy E=K+U (the sum of kinetic energy and gravitational potential energy) at both the initial and final positions, ensuring they remain constant.

<pInitially, for the three spheres, we have:

E_i=K_i+U_i=\frac{mv_i^2}{2}+mgh_i=\frac{mv^2}{2}+mgh

Finally, for the three spheres, we see:

E_f=K_f+U_f=\frac{mv_f^2}{2}+mgh_f=\frac{mv_f^2}{2}

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4 0
3 months ago
A 20.00-kg lead sphere is hanging from a hook by a thin wire 2.80 m long and is free to swing in a complete circle. Suddenly it
Keith_Richards [3271]
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where u is the velocity at the lowest point. Consequently, the modified equation is

= \sqrt{v^{2} + 4gr}

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