Answer:
h = 10 m
Explanation:
Given,
mass of the platform = 50 Kg
Kinetic energy = 5000 J
height from which the diver dove =?
Taking the acceleration due to gravity as 10 m/s²
Using the conservation of energy principle
Kinetic energy is transformed into potential energy
K.E = P.E
K.E = m g h
5000 = 50 x 10 x h
500 h = 5000
h = 10 m
The height from which the diver dove is equal to h = 10 m
Final displacement equals +24484.5 nm. The path difference observed with red light (λ1 = 656.3 nm) with 158 bright spots can be represented as: Δr = 2d2 - 2d1 = 150λ1, leading to the equation 2d2 - 2d1 = 150λ1. Dividing both sides results in: d2 - d1 = 75λ1 - - - - eq1, with d1 being the distance from the beam splitter to the fixed mirror, and d2 indicating the position of the movable mirror when 158 bright spots appear. Then, with 114 bright spots, the path difference is Δr = 2d'2 - 2d1 = 114λ1, simplifying to 2d'2 - 2d1 = 114λ1. Subsequent division gives: d'2 - d1 = 57λ1, where d'2 is the revised position of the movable mirror. The displacement of the movable mirror, (d2 - d'2), can be calculated by subtracting eq2 from eq1, leading to: d2 - d'2 = 75λ1 - 57λ2, with λ1 equal to 656.3 nm and λ2 equal to 434.0 nm. Finally, this gives d2 - d'2 = 75(656.3) - 57(434), resulting in +24484.5 nm.
