Response:
a) 
, b) 
Clarification:
a) The absolute pressure at a depth of 27.5 meters is:
b) The force applied by the water is:
Answer:
A) The updated amplitude = 0.048 m
B) Period T = 0.6 seconds
Explanation: Please refer to the attached documents for the solution.
The answer is (C) 4 beats per second. The number of beats is computed as the difference between the frequencies of the two tuning forks. Plugging in the frequency values yields a result. Thus, the number of observable beats per second will be 4.
Even if we lack details about the size of the pressure cooker or the altitude of its operation, we can reliably assess the force on the lid based on prior knowledge because, similar to boiling water, the pressure buildup inside the cooker increases in line with the rising temperature.
Answer:
a) The jogger's acceleration is 1.5 m/s²
b) The car's acceleration is also 1.5 m/s²
c) Yes, the car covers a distance 76 m greater than the jogger.
Explanation:
a) Acceleration is the change in velocity over a given time interval:
a = (final velocity - initial velocity) / time
For the jogger:
a = (3.0 m/s - 0 m/s) / 2.0 s = 1.5 m/s²
b) For the car:
a = (41.0 m/s - 38.0 m/s) / 2.0 s = 1.5 m/s²
c) To find how far the car has traveled after 2 seconds, use the formula for position under acceleration along a straight path:
x = x₀ + v₀ t + ½ a t²
where
x = position at time t
x₀ = initial position
v₀ = initial velocity
t = elapsed time
a = acceleration
Assuming x₀ = 0 (origin at car's starting point):
x = 38.0 m/s × 2 s + ½ × 1.5 m/s² × (2.0 s)²
x = 79 m
Similarly, position of the jogger after 2 seconds is:
x = 0 m/s × 2 s + ½ × 1.5 m/s² × (2.0 s)² = 3 m
The difference traveled by the car compared to the jogger is 79 m - 3 m = 76 m
