Answer:
2.87 m
Explanation:
Given parameters:
Mass of the ball (m) = 60 g = 0.06 kg
Height of the tube (h) = 0.70 m
Force applied on the ball by compressed air (F) = 3.0 N
Initial velocity of the ball (u) = 0 m/s (Assumed)
Final velocity of the ball at the tube's exit (v) =?
Acceleration of the ball (a) =?
The ball's weight is derived from multiplying mass and gravity. Therefore,
Weight (W) =
Thus, the total force acting on the ball equals the net of upward force minus the weight.
Net force = Air force - Weight
According to Newton's second law, net force equals the mass multiplied by acceleration.
Acceleration (a) is calculated as 40.2 m/s².
Using the motion equation, we find:
Let’s denote the maximum height achieved as 'H'.
Next, we apply the principle of energy conservation from the pipe's peak to the maximum height.
A decrease in kinetic energy equals an increase in potential energy.
Substituting the values, we solve for 'H', yielding:
Hence, the ball ascends to a height of 2.87 m above the top of the tube.