The height measures 69.68 m
Explanation:
Given data
Before striking the ground = 46 % of the total distance
To establish
the height
Solution
We know here acceleration and displacement, which is
d = (0.5)gt²..............1
Here d is the distance, g is the acceleration, and t is time
So, when an object falls it will be
h = 4.9 t²....................2
For the first part of the inquiry
The falling objects account for
54 % of the total distance
0.54 h = 4.9 (t-1)²...................3
Thus,
Now we possess two equations with unknown variables
We can equate both equations
The first equation already solves for h
Substituting h in the second equation allows us to find t
0.54 × 4.9 t² = 4.9 (t-1)²
t = 0.576 s and 3.771 s
We choose here 3.771 s since 0.576 s is negligible; the distance covered in the last second before it impacts the ground is 46 % of the entire fall.
Thus, selecting t = 3.771 s
Then h from equation 2
h = 4.9 t²
h = 4.9 (3.771)²
h = 69.68 m
Thus, the height is 69.68 m
