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3 months ago

Sheri’s cab fare was $32, with a 20% gratuity and no taxes. Sheri wrote a check to the cab driver for $40.

Mathematics

3 answers:

PIT_PIT [12.4K]3 months ago

6 0

Answer:

Paying $40 is $8 above $32, making the tip $8. The fare of $32 is nearly $30, and 20% of that would be $6. Although $8 surpasses $6 slightly, it remains a logical amount.

zzz [12.3K]3 months ago

5 0

Indeed, a fare of $40 is a fair charge for the cab ride.

Explanation

Sheri's cab fare totaled $32, with a gratuity rate of 20%.

The gratuity amount is: $\$32* 20\% = \$32*0.20= \$6.40$

Thus, the total cab fare including gratuity is: $\$32+\$6.40 = \$38.40$

Since Sheri issued a $40 check to the cab driver, it indicates she provided ($40 - $38.40) or an extra $1.60 to the cab driver. Consequently, the $40 payment is reasonable for the cab fare.

babunello [11.8K]3 months ago

0 0

$40 exceeds $32 by $8, indicating an $8 tip. With $32 being close to $30, where 20% equals $6, $8 is marginally more than $6 but still a sensible amount.

The appropriate expression is 1 Over 5 x Superscript minus 8 Baseline y Superscript minus 13 Baseline EndFraction

Step-by-step explanation:

In order to simplify the expression $\frac{3x^{-6}y^{-3} }{15x^{2}y^{10} }$ where x ≠ 0, y ≠ 0, we must work through the given expression.

$\frac{3x^{-6}y^{-3} }{15x^{2}y^{10} }\\= \frac{3}{15} x^{-6-2}y^{-3-10}\\ = \frac{3}{15}x^{-8}y^{-13} \\ =\frac{1}{5}x^{-8}y^{-13} \\$

The appropriate expression is 1 Over 5 x Superscript minus 8 Baseline y Superscript minus 13 Baseline EndFraction

6 0

3 months ago

Tim was given a large bag of sweets and ate one third of the sweets before stopping as he was feeling sick. The next day he ate

Leona [12618]

Answer: Initially, he had 27 sweets.

Step-by-step explanation: The most logical approach is to work backwards from what remained after the third day to the start of the first day.

On the third day, he consumed one-third of his sweets and was left with 8. If we let the total sweets on day three be denoted as a, then one-third of a equals what he ate and the two-thirds left equals 8, giving us:

8/a = 2/3

By cross-multiplying, we find:

8 x 3 = 2a

Therefore, 24 = 2a

This leads to a = 12.

Let the sweets on day two be represented as b. If he consumed one-third of b and was left with 12, we have the same structure; hence:

12/b = 2/3

Cross-multiplying gives:

12 x 3 = 2b

So, 36 = 2b, leading to b = 18.

Denote the number of sweets on day one as x. If one-third of x was eaten and 18 remained, we can set up the equation:

18/x = 2/3

Again, cross-multiplying results in:

18 x 3 = 2x

Which simplifies to 54 = 2x, yielding x = 27.

Thus, Tim received 27 sweets at the start.

3 0

3 months ago

A pile of sand has a weight of 90kg the sand is put into a small bag and a medium bag and a large bag in the ratio 2:3:7

tester [12383]

90kg of sand was divided into 3 bags, constituting a total of 2+3+7=12 sections.
90kg/12=7.5kg
The smaller bag comprises 2 sections, hence it weighs 7.5kg*2=15kg
The medium-sized bag consists of 3 sections, leading to a total weight of 7.5kg*3=22.5kg
The larger bag encompasses 7 sections, resulting in a weight of 7.5kg*7=52.5kg
Thus, the ratio 2:3:7 translates to 15kg:22.5kg:52.5kg
Verifying, 15kg+22.5kg+52.5kg equals 90kg

3 0

2 months ago

Of 162 students honored at an academic awards banquet, 48 won awards for mathematics and 78 won awards for English. There are 14

tester [12383]

Answer: 56/81

Step-by-step explanation:

refer to the attached document

3 0

3 months ago