To isolate C in the equation

start by subtracting P from both sides:

Then, add C to both sides to get:

The answer is D. Step-by-step reasoning: We are provided with the graph of a transformed tangent function. Observing the graph, it shows an upward shift by 2 units. This indicates that the parent function has been displaced 2 units upward. Thus, the new function is of the form. Therefore, options A and C are incorrect. Additionally, a function f(x) with period P transforms into function cf(bx) with period. The graph confirms that the graphed function has. Since, has period. Therefore, the function in option B cannot possess that period. Conversely, the function in option D maintains that period.
Answer:
I think the first one
Step-by-step explanation:
This can be expressed using the general formula for a² – b².
Response:
The probability that a student has a pet, given they do not have any siblings is:
Option: D ( 60%)
Step-by-step breakdown:
Let A represent the situation where a student lacks a sibling.
Let B signify the occurrence that a student has a pet.
Consequently, A∩B refers to the event in which a student is without siblings but possesses a pet.
Let P denote the chance of an event happening.
We need to determine:
P(B|A)
From our knowledge:

From the data provided:
P(A)=0.25
and P(A∩B)=0.15
Thus,

which expressed as a percentage is:

Therefore, the probability is:
60%