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Allushta
3 months ago
9

The present age of Alex is ‘y’ years. Answer the following

Mathematics
2 answers:
Inessa [12.5K]3 months ago
6 0

Hey friend, here’s your answer!

(a) 5 + y

(b) y - 6

(c) 5y

(d) 6 + 3y

I hope this is helpful to you!

PIT_PIT [12.4K]3 months ago
5 0

Answer:

(a) What will his age be after 5 years?

"5 + y" years old

(b) What was his age 6 years ago?

"y - 6" years old

(c) If his grandfather’s age is five times his, how old is his grandfather?

"5y" years old

(d) His father is 6 years older than three times his age. How old is his father?

"6 + 3y" years old

Note: Disregard the quotation marks, ""

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A battery with 20% percent of its full capacity is connected to a charger. Every minute that passes, an additional 5% percent of
Inessa [12570]

Response:

The connection between battery capacity and time is:

Y=0.05t+0.2

The associated graph is provided.

Step-by-step explanation:

We will plot the battery's charged capacity against time.

The charging rate remains steady; hence, the relationship is linear.

Initially, at time t=0, the battery's capacity measures 0.2 (or 20%).

With each passing minute, an additional 5% of its capacity is accumulated. Thus, at t=1, the capacity becomes 0.2 + 0.05 = 0.25 (or 25%).

We can derive the slope for the linear function as:

m=\dfrac{\Delta Y}{\Delta t}=\dfrac{0.05}{1}=0.05

Consequently, the correlation between battery capacity and time is:

Y=0.05t+0.2

3 0
3 months ago
Tanmay had some chocolates with him. He gave one-third of them to Akash and one-fifth of them to Sharad. Tanmay could do so with
babunello [11817]

Answer:

Possible values for X include;

15, 30, 45, 60, and so on

Step-by-step explanation:

The parameters provided are

Number of chocolates Tanmay possessed = X

Number of chocolates given to Akash = 1/3 × X

Number of chocolates given to Sharad = 1/5 × X

Consequently, since both 3 and 5 divide X,

3 × 5 = 15 is the smallest single factor of X.

Thus, the values of X based on this minimum factor are as follows;

15 × 1 = 15

15 × 2 = 30

15 × 3 = 45

15 × 4 = 60

Therefore, potential values for X form an arithmetic series: a + (n - 1) × d

Where:

a = 15

n = 1, 2, 3, 4,...

d = 15

This results in;

15, 30, 45, 60

7 0
3 months ago
El área de una propiedad en metros cuadrados, mide 704/5. Se construye una casa que ocupa 5/6 del área total. La mitad del área
tester [12383]

Answer:

The remaining area available for construction is \frac{704}{60}\ m^{2}

Step-by-step analysis:

The inquiry in English reads

The total area of a property, measured in square meters, amounts to 704/5. A house is constructed occupying 5/6 of this area. Half of the leftover space is utilized for a terrace; thus, how much area remains for additional construction?

We know that

The total area is represented by the fraction 6/6

A house accounts for 5/6 of the entire area

Thus, the remaining area is (6/6)-(5/6)=1/6 of the overall area

If half of this leftover area is designated for a terrace

then

the terrace occupies (1/6)/2=1/12 of the total area

consequently,

The area remaining for construction is 1/12 of the total area

therefore

(\frac{1}{12})\frac{704}{5} =\frac{704}{60}\ m^{2}

8 0
3 months ago
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