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13 days ago

Three blocks of the same mass are placed in front of you. Block A has a volume of

Chemistry

1 answer:

KiRa [2.9K]13 days ago

8 0

Given:

There are three blocks, labeled A, B, and C, each with identical mass.

The dimensions of block A, B, and C are 3.0 cm, 5.0 cm, and 10.0 cm, respectively.

To Find:

Determine which block exhibits the greater density.

Solution:

Density $\rho$ is defined as:

$\rho=\dfrac{M}{V}$ ......1 )

Here, V represents volume.

The volume V for a cube can be calculated as:

$V=a^3$ .......2 )

( In this context, a denotes the cube's side length )

From equation 1, we observe that if mass is constant, density is inversely proportional to volume.

Consequently, the cube with the smallest side will possess the highest density, which, in this scenario, is the block measuring 3 cm.

Thus, this concludes our solution.

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C2H5OH(aq) + MnO− 4 (aq) → Mn2+(aq) + CH3COOH(aq) of acetic acid from ethanol by the action of permanganate ion in acidic soluti

Tems11 [2777]

Response:

Ethanol serves as a reducing agent. $(C_2H_5OH)$

The lowest integer coefficient for $MnO_4^-$ in the balanced equation is 4

Clarification:

A redox reaction, or oxidation-reduction reaction, is defined as one in which oxidation and reduction processes occur simultaneously.

Oxidation is the process whereby a substance loses electrons, resulting in an increase in oxidation state. In contrast, reduction entails a substance gaining electrons, leading to a decrease in oxidation state.

Reducing agents enable other substances to undergo reduction while becoming oxidized themselves.

Conversely, oxidizing agents facilitate other substances' oxidation while being reduced in the process.

For the chemical reaction in question, the half-reaction would be:

Oxidation:

Reduction:

To balance the oxygen atoms on both sides

$C_2H_5OH(aq)+MnO_4^-(aq)\rightarrow CH_3COOH(aq)+Mn^{2+}(aq)$

For oxidation:

For reduction:

$C_2H_6O\rightarrow C_2H_4O_2$

$MnO_4^-\rightarrow Mn^{2+}$ Then balance the hydrogen atoms on both sides.

For oxidation:

For reduction:

$C_2H_6O+H_2O\rightarrow C_2H_4O_2$

Lastly, balance the charge. $MnO_4^-\rightarrow Mn^{2+}+4H_2O$

For oxidation: For reduction:

$C_2H_6O+H_2O\rightarrow C_2H_4O_2+4H^+$

To balance the electrons, multiply the oxidation reaction by 5 and the reduction by 4 before combining both equations for a balanced redox reaction.

$MnO_4^-+8H^+\rightarrow Mn^{2+}+4H_2O$ Oxidation:

Reduction:

The finalized balanced chemical equation in acidic conditions will be:

$C_2H_6O+H_2O\rightarrow C_2H_4O_2+4H^++4e^-$

$MnO_4^-+8H^++5e^-\rightarrow Mn^{2+}+4H_2O$

In this redox process, ethanol acts as the reducing agent while the permanganate ion serves as the oxidizing agent.

4 0

15 days ago

A sample of an unknown substance has a mass of 0.158 kg. If 2,510.0 J of heat is required to heat the substance from 32.0°C to 6

alisha [2963]

Specific heat refers to the quantity of heat a material can absorb or release to alter its temperature by one degree Celsius. To calculate specific heat, we apply the equation for the heat absorbed by the system. The heat taken in or released by a system can be expressed by multiplying the mass of the substance by its specific heat capacity and the change in temperature. The formula is:
Heat = mC(T2-T1)
By substituting the provided values, we can find C, the specific heat of the substance.
2510 J = 0.158 kg (1000 g / 1 kg)(C)(61.0 - 32.0 °C) C = 0.5478 J/g°C

8 0

1 month ago

Read 2 more answers

Put the list in chronological order (1–5).

alisha [2963]

Explanation:

Filtration serves as a method of separation where solid particles that are suspended in a liquid are isolated by passing the mixture through filter paper's pores. This process ensures that the solid particles accumulate on the filter paper and the liquid flows out through the filter paper's pores.

The ordered sequence of the steps provided is:

Measure and fold the filter paper.
Insert the filter paper into the funnel, then position the funnel above the Erlenmeyer flask.
Let the solid/liquid mixture pass through the filter.
Rinse the filter paper that holds the mixture with water.
Measure the weight of the dry filter paper along with the copper.

4 0

1 month ago

Read 2 more answers

The production of NOx gases is an unwanted side reaction of the main engine combustion process that turns octane, C8H18, into CO

lorasvet [2795]

Answer:

710.33 g NO2

Explanation:

2 C8H18 + 25 O2 → 16 CO2 + 18 H2O

(800 g octane) / (114.2293 g C8H18/mol x (25/2)) = 87.54 mol O2 utilized for combusting octane

$87.54 mol O2 x \frac{15}{85}$ = 15.44 mol O2 used for generating NO2