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1 month ago

Compaction is most significant as a lithification process for sedimentary rocks composed of sand-sized particles. True False

Chemistry

1 answer:

VMariaS [2.9K]1 month ago

8 0

Response:

FALSE

Rationale:

Sedimentary rocks are defined as rocks formed through the processes of compaction and cementation. Initially, sediments derived from various locations must accumulate. Over time, these deposited sediments undergo substantial compaction due to the weight of the layers above. This process converts loose sediments into solid rock. This is the process through which sedimentary rocks, comprised of sand-sized particles, are formed. For instance, examples include Shale, Sandstone, and Mudstone.

Thus, both compaction and cementation are crucial in the formation of sedimentary rocks.

Therefore, the statement above is False.

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A 1.00 l solution contains 3.50×10-4 m cu(no3)2 and 1.75×10-3 m ethylenediamine (en). the kf for cu(en)22+ is 1.00×1020. what is

castortr0y [3046]

<span>Response: A 1.00 L solution that includes 3.00x10^-4 M Cu(NO3)2 and 2.40x10^-3 M ethylenediamine (en). Contains 0.000300 moles of Cu(NO3)2 and 0.00240 moles of ethylenediamine. Using the formula Cu(en)2^2+ 0.000300 moles of Cu(NO3)2 reacts with double that amount of en = 0.000600 mol of en. Thus, 0.00240 moles of ethylenediamine - 0.000600 mol of en reacted leaves 0.00180 mol en unreacted. According to the formula Cu(en)2^2+ 0.000300 moles of Cu(NO3)2 reacts to yield an equivalent of 0.000300 moles of Cu(en)2^2+ The formation constant Kf for Cu(en)2^2+ is 1x10^20. Therefore, 1 Cu+2 and 2 en --> Cu(en)2^2+ Kf = [Cu(en)2^2+] / [Cu+2] [en]^2 1x10^20 = [0.000300] / [Cu+2] [0.00180 ]^2 Solving for [Cu+2] gives [Cu+2] = [0.000300] / (1x10^20) (3.24 e-6) Thus, Cu+2 = 9.26 e-19 Molar. Since Kf only has 1 significant figure, round that to 9 X 10^-19 Molar Cu+2.</span>

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1 month ago

Which example best demonstrates stewardship of the atmosphere

KiRa [2933]

The question is incomplete. Nonetheless, I gave an example of atmospheric stewardship. First, it’s important to understand that stewardship implies a duty for humans to care for and preserve our environment, which includes the atmosphere. One way to demonstrate this is by changing how we travel; for example, opting to bike instead of using a car. This choice would help decrease greenhouse gas emissions since bicycles do not release harmful gases.

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1 month ago

What is the kinetic energy acquired by the electron in hydrogen atom, if it absorbs a light radiation of energy 1.08x101 J. (A)

eduard [2782]

Explanation:

The following data has been provided:

Energy of radiation absorbed by the electron in the hydrogen atom = $1.08 \times 10^{-17} J$

As energy is absorbed in the form of a photon, the frequency is calculated accordingly:

E = $h \nu$

$1.08 \times 10^{-17} J$ = $6.626 \times 10^{-34} Js \times \nu$

$\nu$ = $0.163 \times 10^{17} s^{-1}$

or, $\nu$ = $1.63 \times 10^{16} s^{-1}$

It is known that $\nu = \frac{c}{\lambda}$

$1.63 \times 10^{16} s^{-1} = \frac{3 \times 10^{8} m/s}{\lambda}$

$\lambda$ = $1.84 \times 10^{-8} m$

According to the De-Broglie equation $\lambda = \frac{h}{p}$

with p = $m \times \nu$

So, $\lambda = \frac{h}{m \times \nu}$

$m \times \nu = \frac{6.626 \times 10^{-34} Js}{1.84 \times 10^{-8} m}$ = $3.6 \times 10^{-26} J/m$

Squaring both sides gives us:

$(m \times \nu)^{2}$ = $(3.6 \times 10^{-26} J/m)^{2}$

$12.96 \times 10^{-52}$ = $m \times \nu^{2} = \frac{12.96 \times 10^{-52}}{m}$

where m = mass of the electron

Therefore, $m \times \nu^{2} = \frac{12.96 \times 10^{-52}}{m}$

= $\frac{12.96 \times 10^{-52}}{9.1 \times 10^{-31}}$

= $1.42 \times 10^{-21}$ J

Since K.E = $\frac{1}{2}m \nu^{2}$

= $\frac{1.42 \times 10^{-21} J}{2}$

= $0.71 \times 10^{-21} J$

Our conclusion is that the kinetic energy gained by the electron in the hydrogen atom is $7.1 \times 10^{-22} J$ .

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1 month ago

Calculate the mass, in grams, of a single tellurium atom (mte = 127.60 amu ).

castortr0y [3046]

1 atomic mass unit (amu) represents the mass of an atom or is used to measure mass on an atomic scale. It is also referred to as a dalton, abbreviated as Da, while atomic mass unit is indicated as amu.

1 amu can be translated into grams as follows:

$1 amu = 1.6 * 10^-2^4 g$

$Mass of Te = 127.6 amu$

For conversion into grams:

$M = (127.6 ) * 1.6 * 10^-2^4 g$

$M = 204.16 * 10^-2^4 g$

Therefore, the mass of Te is 204.16 * 10^-2^4 g

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1 month ago

Read 2 more answers

Put the following elements into five pairs of elements that have similar chemical reactivity: F, Sr, P, Ca, O, Br, Rb, Sb, Li, S

Anarel [2989]

Explanation:

Elements provided:

F, Sr, P, Ca, O, Br, Rb, Sb, Li, S

Elements sharing similar reactivity belong to the same group in the periodic table, indicating that those in the same column exhibit comparable reactivity. Here are the identified groupings:

Li and Rb are alkali metals in group 1

Ca and Sr are alkaline earth metals in group 2

F and Br are halogens in group 7

O and S belong to group 6

P and Sb are classified in group 5 of the periodic table

Thus, these classifications illustrate elements with the same chemical characteristics.

7 0

1 month ago