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viktelen
22 days ago
6

Find a122 of the sequence 5, 8, 11

Mathematics
1 answer:
Svet_ta [9.5K]22 days ago
8 0
To find a122 in the sequence beginning with 5, 8, 11, we recognize this series is arithmetic.
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The length of a rectangle is measured as 370mm correct to 2 significant figures.
Svet_ta [9500]

Answer:

UB: 375

Step-by-step explanation:

370mm rounded to 2 significant figures is..

UB: 375

LB:365

Please rate me 5 stars and thank me:)

5 0
1 day ago
9. The purpose of statistical inference is to provide information about the.
AnnZ [9099]
<span>c. demographics based on the details in the population.#9

#10</span><span>b. 81 and 18.</span>
6 0
18 days ago
Five thousand tickets are sold at​ $1 each for a charity raffle. Tickets are to be drawn at random and monetary prizes awarded a
babunello [8412]

Response:

the expected value of this raffle if you purchase 1 ticket = -0.65

Breakdown of the calculation:

Details:

5,000 tickets are sold at​ $1 each for a charitable raffle

Winners will be chosen at random with cash prizes as follows: 1 prize of ​$500​, 3 prizes of ​$300​, 5 prizes of ​$50​, and 20 prizes of​ $5.

Therefore, the value and its respective probability can be calculated as follows:

Value                              Probability

$500 - $1 = $499              1/5000

$300 - $1 = $299              3/5000

$50 - $1 = $49                    5/5000

$5 - $1 = $4                     20/5000

-$1                           1 - 29/5000 = 4971/5000

The expected value of the raffle when buying 1 ticket is computed as follows:

E(x) = \sum x * P(x)

E(x) = (499 * \dfrac{1}{5000} + 299 *\dfrac{3}{5000} + 49 *\dfrac{5}{5000} + 4 * \dfrac{20}{5000} + (-1 * \dfrac{4971}{5000} ))

E(x) = (0.0998 + 0.1794+0.049 + 0.016 + (-0.9942 ))

E(x) = (0.3442 -0.9942 )

\mathbf{E(x) = -0.65}

So, the expected value of this raffle when one ticket is purchased = -0.65

7 0
7 days ago
Margie received her store order on 12/3/16 at 4AM. She just opened one of the
Inessa [9000]

Answer:

Expiration Date: 1/17/2017

Expiration Time: 4:00am

Preparation Date: 12/3/2016

Preparation Time: 4:00am

Initial Usage Date: 12/7/2016

Detailed Breakdown:

An illustrative depiction of the question has been provided in an image format for clarity.

From the information given, it is noted that her store order arrived on 12/3/2016 at 4am, confirming that both the prep date and time are 12/3/2016 and 4am respectively. The product has a printed expiration date of 1/17/2017, logically indicating that its expiration time is also 4am, in line with the prep time; adding 24 hours leads us back to the same time on the expiration date. Furthermore, we were informed that she utilized the product on 12/7/2016, which marks the initial use date. Based on this information, we can summarize as follows:

Expiration Date: 1/17/2017

Expiration Time: 4:00am

Preparation Date: 12/3/2016

Preparation Time: 4:00am

Initial Usage Date: 12/7/2016

8 0
1 month ago
The graph of f(x) = x2 is translated to form g(x) = (x – 5)2 + 1. Which graph represents g(x)?
Leona [9271]
<span>The graph will shift 5 units to the right and 1 unit upwards, forming a parabola that opens up with its vertex positioned at (5, 1).

Explanation:
The subtraction of 5 from x prior to squaring indicates a horizontal movement of 5 units to the right.

The addition of 1 signifies a vertical shift of 1 unit up.

This transformation follows the vertex form of a parabola, y=a(x-h)^2 + k, where (h, k) represents the vertex. In this case, h is 5 and k is 1, placing the vertex at (5, 1).</span>
6 0
27 days ago
Read 2 more answers
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