Answer:
78.96 g of NaC2H3O2
Explanation:
The following information is provided:
- The solution's volume is 350 mL
- The solution's molarity is 2.75 M
- The molar mass of NaC2H3O2 is 82.04 g/mol
We need to find the mass of the solute:
First, we calculate the number of moles:
Moles = Molarity × Volume
Thus;
Moles of solute = 2.75 M × 0.350 L
= 0.9625 moles
Next, we find the mass:
Mass = Moles × Molar mass
= 0.9625 moles × 82.04 g/mol
= 78.9635 g
= 78.96 g
Therefore, the amount of NaC2H3O2 required is 78.96 g
Response:
Ionic, metal, organic
Clarification:
For this scenario, we should examine each compound:
-) 
In this compound, there is a non-metal atom (Cl) paired with a metal atom (Ca). This leads to a significant difference in electronegativity, indicating that an ionic bond will form. Ions can be generated:

The positive ion would be
while the negative ion is
. Thus, we have an ionic compound.
-) 
Here, we are looking at a single atom. Consulting the periodic table shows that this atom belongs to the transition metals section (central part of the periodic table). Hence, Cu (Copper) is identified as a metal.
-) 
Within this molecule, carbon and hydrogen are linked by single bonds. The difference in electronegativity between C and H is insufficient to lead to ion formation. Therefore, we have covalent bonds. This property is typical of organic compounds. (Refer to figure 1)
Answer: The mass of Si in kilograms is, 
Explanation:
Given that the Si concentration in an Fe-Si alloy is 0.25 weight percent, this translates to:
Mass of Si = 0.25 g = 0.00025 kg
Mass of Fe = 100 - 0.25 = 99.75 g = 0.09975 kg
Density of Si = 
Density of Fe = 
Next, we need to find the quantity of Si in kilograms per cubic meter of alloy.
Si concentration in kilograms = 
Si concentration in kilograms = 
By substituting all the provided values into this formula, we arrive at:
Si concentration in kilograms = 
Si concentration in kilograms = 
Hence, the mass of Si in kilograms is, 
First scenario:
IV: soda, gatorade, orange juice, and water
DV: state of the liquids listed above
Control: freezer and ice tray
Second scenario:
IV: laundry detergent, water
DV: cleanliness of the squares post-wash
Control: chocolate, cloth type, cloth squares
Third scenario:
IV: type of water used, pea plant
DV: growth of the pea plant
Control: pots and daily water amount for the plant
Specific heat refers to the quantity of heat a material can absorb or release to alter its temperature by one degree Celsius. To calculate specific heat, we apply the equation for the heat absorbed by the system. The heat taken in or released by a system can be expressed by multiplying the mass of the substance by its specific heat capacity and the change in temperature. The formula is:
Heat = mC(T2-T1)
By substituting the provided values, we can find C, the specific heat of the substance.
2510 J = 0.158 kg (1000 g / 1 kg)(C)(61.0 - 32.0 °C) C = 0.5478 J/g°C