Answer:
The answer I think fits this question is D.
Explanation:
I hope this is helpful and accurate.
Answer with Explanation:
Concepts and reasoning
The principle for addressing this question is that a capacitor in an RC circuit allows current to flow until fully charged. Once charged, it prevents any further current from moving through. Conversely, the situation is different with an inductor in an RL circuit. In accordance with Faraday's law, an inductor generates an electromagnetic force to counteract the applied voltage, but when no change in flux occurs, it behaves akin to a regular wire as if the inductor is absent.
In the accompanying diagram, a resistor is connected in series with a capacitor.
As we observe
the voltage across both the capacitor and the source.
Voltage across a resistor in an RC circuit.
Voltage across a resistor in an RL circuit.

Answer:
Please include the diagrams and repost them.
Impulse can be equated to the force associated with momentum change, expressed as F*t = mv - mu
Given the mass and speed values are provided, apply the formula from the right-hand side:
mass, m = 1.7 x 10^27 kg
initial velocity, u = 0.991 x (3 x 10^8) = 2.973 x 10^8
final velocity, v = 0.994 x (3 x 10^8) = 2.982 x 10^8
Consequently, the calculation is:
Impulse = mv - mu
= [(1.7 x 10^27) x (2.982 x 10^8)] - [(1.7 x 10^27) x (2.973 x 10^8)]
= (5.0694 x 10^35) - (5.0694 x 10^35)
= 0
Answer:
0.130
Explanation:
The coefficients of static friction recorded for each trial are listed as follows:
1. 0.053
2. 0.081
3. 0.118
4. 0.149
5. 0.180
6. 0.198
Adding these coefficients together results in: 0.053 + 0.081 + 0.118 + 0.149 + 0.180 + 0.198
= 0.779
Consequently;
the mean coefficient of static friction = 
= 
= 0.12983
The mean coefficient of static friction is 0.130