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IrinaVladis
3 months ago
6

Martha was leaning out of the window on the second floor of her house and speaking to Steve. Suddenly, her glasses slipped from

her nose. The glasses hit the ground in 2.2 seconds. Neglecting the effects of air resistance, answer the questions below. A. What is the height of the window from the ground? B. What was the impact velocity of the glasses?
Physics
1 answer:
serg [3.5K]3 months ago
6 0
The height from which the glasses fell is s = 23.72 m and the impact speed is v = 21.56 m/s². Explanation: Using the time taken to hit the ground (t) = 2.2 seconds, we can apply the formula s = u t + 0.5 g t² with initial velocity u = 0 m/s and g = 9.8 m/s²: s = 0 + 0.5 × 9.8 × 2.2², resulting in s = 23.72 m. For the impact velocity, we use the equation v = √(2gh), yielding v = √(2 × 9.8 × 23.72) = √464.912, leading to v = 21.56 m/s².
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kicyunya [3294]
To counteract a 58 mph crosswind, the western component of the trajectory must be accounted for. Consequently, directing towards the northwest creates a 45-degree angle, aligning with the destination. This triangle's third vertex is located at the destination, with the right angle positioned there. The western aspect of their flight represents the triangle's base, while the vertical side reflects the resultant path, and the hypotenuse indicates the actual distance traveled. Since the 58 mph crosswind was countered by flying in a northwest direction, the distance from the starting point to the destination should equal the westward segment of their journey. The hypotenuse can be determined via the square root of twice the dimension of the identical sides.
c = sqrt (58^2 + 58^2) = sqrt (6728) = 82.02

An alternative method:

c = sqrt (2) * 58 = 1.414 * 58 = 82.02

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5 0
2 months ago
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Four wires are made of the same highly resistive material, cut to the same length, and connected in series. Wire 1 has resistanc
ValentinkaMS [3465]

Answer:

V_2 = \frac{R_2 V_0}{R_1+R_2+R_3+R_4}

Explanation:

The four wires are arranged in series: this setup indicates that the same current passes through them, while the total voltage from the battery, V0, equals the combined voltages across each resistor:

V_0=V_1+V_2+V_3+V_4

Additionally, the total resistance for this series configuration is

R_{eq}=R_1+R_2+R_3+R_4

Using Ohm's law, we can determine the voltage V2 across wire 2:

V_2 = R_2 I (1)

Here, I represents the entire current flowing through the circuit, which is calculated as:

I=\frac{V_0}{R_{eq}}=\frac{V_0}{R_1+R_2+R_3+R_4}

By substituting into equation (1), we derive V2:

V_2 = \frac{R_2 V_0}{R_1+R_2+R_3+R_4}

8 0
2 months ago
Rod A and rod B are cylindrical rods made of the same metal. amd they differ only in size. Rod B has double the length and doubl
Keith_Richards [3271]

Answer:

The answer I think fits this question is D.

Explanation:

I hope this is helpful and accurate.

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3 months ago
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Two parallel plates of area 2.34*10-3 M2 have 7.07*10-7C of charge placed on them. A6.62*10-5C charge q1 is placed between the p
kicyunya [3294]

Response:

The force acting on the q_1 is F = 2.25*10^{3} \ N

Clarification:

According to the problem statement,

The area is A = 2.34*10^{-3} \ m^2

The amount of charge placed on them is q = 7.07 * 10^{-7} C

The charge located between the plates is q_1 = 6.62 *10^{-5} C

The electric field surrounding the plate is mathematically expressed as

E = \frac{q}{A \epsilon_o}

Substituting in the values

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The force on the charge q_1 is mathematically described as

F = q_1 * E

Replacing values

F = 6.62 *10^{-5} * 34*10^{6}

F = 2.25*10^{3} \ N

8 0
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