Martha was leaning out of the window on the second floor of her house and speaking to Steve. Suddenly, her glasses slipped from

The right answer is (a).

Solar panels create electric current through the photoelectric effect, which describes how photons strike certain material surfaces, resulting in the release of electrons when light with the correct frequency hits them. A photon will interact with an electron on the panel, causing it to be ejected from the panel's surface.

As the illumination on the panel becomes brighter, the intensity of the light rises, indicating an increase in the number of photons. Each photon has the potential to liberate an electron; thus, as the number of incoming photons rises, so does the quantity of freed electrons. Given that the photoelectric current reflects the rate at which these electrons flow, an increase in light intensity leads to a corresponding rise in the photoelectric current.

If the frequency of the light is increased without a change in brightness, the photoelectric current remains the same because the total number of photons does not increase. Yet, the electrons that are ejected do escape with higher kinetic energy. However, since the total number of electrons liberated stays unchanged, the current remains constant regardless of the electrons' increased energy. Thus, option b is incorrect.

Increasing the wavelength of the light means the energy of the photons decreases. This would cause the emitted electrons to have lower energy. However, if the brightness is consistent, the number of electrons remains the same, and as a result, there would be no change in the photoelectric current. Therefore, choice (c) is also incorrect.

The correct answer is (a). To generate the needed current, the brightness of the incident light must be increased.

Answer:3.87*10^-4

Explanation:

To determine the mass reduction, delta mass Xe, of the xenon nucleus due to its decay, we first use the provided wavelength of the gamma radiation to calculate its frequency via c = freq*wavelength.

From C=f*lambda we set up: 3*10^8=f*3.44*10^-12.

Solving gives frequency F=0.87*10^20 Hz.

Next, we calculate the emitted energy using the equation E=hf, which translates to E=f*Planck's constant.

Thus, E=0.87*10^20*6.62*10^-34, resulting in E=575.94*10^(-16).

This energy is then converted from joules to MeV.

Utilizing the formula E=mc^2, with c^2 = 931.5 MeV/u, enables us to find the reduction in mass, yielding

3.87*10^-4 u.

Answer:

Part A: 7.75 m/s

Part B: 2330.8 kN

Part C: 24.03 kN

Part D: 4.8 kN

Part E:

Part F: Option D

Bending one's legs lengthens the duration of force application from the ground, resulting in a reduction of the applied force.

Explanation:

Part A

Using the fundamental kinematic equations

where v represents the velocity just before ground impact, g denotes gravitational acceleration, u signifies initial velocity, and h is the fall height.

With the initial velocity at zero, thus:

Plugging in 10 m/s² for g and 3 m for h gives:

Part B

The force exercised by the leg can be expressed as

F = PA where P is pressure, F indicates force, and A denotes the cross-sectional area of the bone.

With a substitution of 2.3 cm or 0.023m for d and for P, we derive the force as:

Part C

The fundamental kinematic equations from part (a) can also be rearranged to show:

and solving for a yields

where a is the acceleration and signifies the change in length.

Using the previously derived value from part a, 7.75 m/s for v, and 0.01 m for gives us:

The force felt by the man is given by:

Part D

A similar approach with the fundamental kinematic equations shows:

and solving for a indicates:

where a is the acceleration and denotes the change in height.

The force experienced can thus be defined as .

For substitution, we use m = 80 Kg, and 0.5m for \triangle h along with other values calculated in part c.

Part E

Part F

Bending one's legs extends the period over which the force acts, thus lessening the overall force exerted by the ground.