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almond37
21 day ago
5

A cup is 6.4 cm tall, not including a 0.6 cm lip. Cups are stacked inside one another. You may want to draw a diagram to help yo

u see how the height of the stack of cups increases. Select the function that represents the height of a stack of cups in terms of the number of cups in the stack. Select a Value The number of cups in a 18.4 cm high stack is: Select a Value
Mathematics
1 answer:
PIT_PIT [9.1K]21 day ago
0 0
To understand the stacking of cups, start with the height of one cup plus its lip's height. Following that, continue to add the height of each lip until the desired total height is reached. Thus, the total number of cups needed is 19.
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In a state where tax is 5%, Jane bought a telescope and paid $4.55 in tax. What is the price of the telescope?
tester [8842]
The telescope’s cost is $91

4.55 divided by 5% (0.05) equals 91.
7 0
1 day ago
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Which is the solution of the quadratic equation (4y – 3)2 = 72? y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction a
Inessa [9000]

Answer:

y = \frac{3 + 6\sqrt{2} }{4} y y = \frac{3 - 6\sqrt{2} }{4}

y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction y = StartFraction 3 menos 6 StartRoot 2 EndRoot Over 4 EndFraction

Explicación paso a paso:

La ecuación cuadrática que tenemos es (4y - 3)² = 72

Debemos encontrar el valor de y.

Ahora, 4y - 3 = ± 6√2

⇒ 4y = 3 ± 6√2

⇒ y = \frac{3 + 6\sqrt{2} }{4} y y = \frac{3 - 6\sqrt{2} }{4}

Por lo tanto, las soluciones son y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction y y = StartFraction 3 menos 6 StartRoot 2 EndRoot Over 4 EndFraction (Respuesta)

6 0
1 month ago
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The track team is trying to reduce their time for a relay race. First they reduce their time by 2.1 minutes. Then they are able
PIT_PIT [9117]
The initial time was 15.7 minutes.

Explanation of steps:

Let x represent the initial time (in minutes).

The relay team is working on minimizing their relay race duration.

First, they cut down their time by 2.1 minutes.

Afterwards, they manage to reduce that time by 10 percent.

If the concluding time ends up being 3.96 minutes, then

x-t1-t2= 3.6
x= 3.6+ t1+ t2
x= 3.6+ 2.1+ 10
x= 15.7

Thus, their starting time was 15.7 minutes.
3 0
16 days ago
Select the correct answer from each drop-down menu.
AnnZ [9099]

Answer:

The answer is 7

Step-by-step explanation:

To find the base area of the triangular pyramid:

(base x height) / 2 = (4 x 3.5) / 2 = 7 in²

5 0
26 days ago
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The data set represents the number of rings each person in a room is wearing. 0, 2, 4, 0, 2, 3, 2, 8, 6 What is the interquartil
Leona [9271]
D1,..,d9 = 0,0,2,2,2,3,4,6,8 //there are 9 values, presented in ascending order
Q2 (median) = d5 = 2 //middle value
Q1 = (d2+d3) / 2 = (0+2)/2 = 1
(Q1 represents the median of d1,d2,d3,d4, but as there is no singular middle element among four, the average is computed)
Q3 = (d7+d8) / 2 = (4+6)/2 = 5
interquartile range = IQR = Q3 - Q1 = 5 -1 = 4
final answer: 4

4 0
1 month ago
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