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RUDIKE
2 months ago
14

In this lab, you will use a dynamics track to generate collisions between two carts. If momentum is conserved, what variable cha

nge would result in a velocity change after a collision? In the space below, write a scientific question that you will answer by doing this experiment.
Physics
2 answers:
Keith_Richards [3.2K]2 months ago
8 0

In collision-related situations, momentum remains constant.

Thus, we can deduce:

m_1v_{1i} + m_2v_{2i} = m_1 v_{1f} + m_2v_{2f}

To resolve these problems we also need another equation concerning the restitution coefficient:

v_{2f} - v_{1f} = e(v_{1i} - v_{2i})

With these two equations, we can calculate the velocities after a collision.

Here, the contact force brings about changes in velocity during their interaction.

This represents the impulse that occurs when the two objects are briefly in contact during the collision, which modifies their velocities.

Maru [3.3K]2 months ago
5 0

How does altering the mass impact the interactions between colliding objects?

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Define kinetic energy and thermal energy. Describe what happens to each as the temperature of a substances increases.
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Kinetic energy refers to the energy an object possesses while in motion, whereas thermal energy corresponds to heat energy. In situations where heat increases in materials, such as a solid turning into a liquid, the molecules start to move more rapidly, resulting in a rise in kinetic energy.
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The ballistic pendulum was invented in 1742 by English mathematician Benjamin Robins. It consists of an initially stationary pen
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Answer:

What is your question?

Please feel free to modify or inquire in the comments.

Thank you.

Explanation:

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A coffee company wants to make sure that their coffee is being served at the right temperature. if it is too hot, the customers
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The population mean is parameter = 65 c

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1 month ago
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A baseball is hit high into the upper bleachers of left field. Over its entire flight the work done by gravity and the work done
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Explanation:

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1 month ago
A solid conducting sphere carrying charge q has radius a. It is inside a concentric hollow conducting sphere with inner radius b
Softa [3030]

Response:

Clarification:

Refer to the diagram indicating the charges on the specified sphere (see attachment).

The electric field at the stated positions is

E(r) = 0 for r≤a.  Equation 1

E(r) = kq/r² for a<r<b.   Equation 2

E(r) = 0 for b<r<c.      Equation 3

E(r) = kq/r² for r>c.    Equation 4.

We understand that electric potential correlates with the electric field through

V = Ed

A. To compute the potential at the outer surface of the hollow sphere (r=c), we determine that the electric field there is

E = kQ / r²

Then,

V = Ed,

At d = r = c

Thus,

Vc = (kQ / c²) × c

Vc = kQ / c

As a result, the total charge Q consists of +q, -q, and +q

Hence, Q = q - q + q = q

V = kq / c

B. To calculate the potential at the inner surface of the hollow sphere (r=b), we have

V = kQ/r

V = kQ / b,   noting that r = b

So, Q = q

V = kq / b

C. At r = a

Following from equation 1:

E(r) = 0 for r≤a.  Equation 1

The electric field at the surface of the solid sphere is 0, E = 0N/C

Thus,

V = Ed = 0 V

Consequently, the electric potential at the solid sphere's surface is 0.

D. At r = 0

The electric potential can be determined by

V = kq / r

As r approaches 0,

V = kq / 0

V approaches infinity.

8 0
2 months ago
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